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Plane Geometry - Bruce E. Shapiro

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270 SECTION 46. HYPERBOLIC GEOMETRYSuppose that F ≠ A (RAA). Then AB ‖ F G by the alternate interiorangles theorem. This means that B ≠ G (otherwise AB would intersectF G which is not possible for parallel segments).Hence □ABGF is a rectangle, which is not possible in hyperbolic geometry.Hence the RAA hypothesis is false. Hence F = A and thus B = G. Thismeans that□ABCD ∼ = □A ′ B ′ C ′ D ′« CC BY-NC-ND 3.0. Revised: 18 Nov 2012

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