lecture notes 13
lecture notes 13
lecture notes 13
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.Surface Integral of Vector Field.Let F = (P, Q, R) be a continuous vector field defined in a domaincontaining a smooth oriented surface S, with unit normal vector field.Define the flux of F across S, or the surface integral of F over S as∫∫∫∫( )∂(y, z) ∂(z, x) ∂(x, y)F · n dS = (P, Q, R) · , , du dvS∫∫D∂(u, v) ∂(u, v) ∂(u, v)= P dydz + Q dzdx + R dxdy.. SRemark. If we change the orientation of S, the surface integral willchange by a minus sign.. . . . . .