Weighted Averages and Relative Atomic Mass PowerPoint

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<strong>Weighted</strong> Average Average quiz score = Σ(testscores) x (relative abundance) 10•(0.2) + 9•(0.1) 9+ 8•(0.3) 8+7•(0.1) + 6•(0.2) 6+ 2•(0.1) 2 2.0 + 0.9 + 2.4 + 0.7 + 1.2 + 0.2 =7.4 This is the same result we obtainedearlier.

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Why bother? At this point you may be saying,“That method looks like a lot ofwork. Why would I want to use it?” We probably wouldn’t t use it forcalculating the average of 10 quizscores, but what if you had 100scores, or 1000 to do?

Page 1 and 2: Weighted AveragesHow relative atomi
Page 3 and 4: An Example Let’s s imagine a clas
Page 5 and 6: Weighted Average The Greek letter s
Page 7 and 8: Weighted Average There was only 1 s
Page 9: Weighted Average Because the data c
Page 14 and 15: Relative Atomic Mass Actually, we h
Page 16 and 17: An Example Problem To get chlorine
Page 18: Conclusion By rounding an element

Weighted Averages and Relative Atomic Mass PowerPoint

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