Weighted Averages and Relative Atomic Mass PowerPoint

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Weighted AverageScoreRelative Abundance10 0.29 0.18 0.37 0.16 0.22 0.1Total 1.0The total of the relative abundances must be1.0 (or very close.)

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Weighted AverageScoreRelative Abundance10 0.29 0.18 0.37 0.16 0.22 0.1Total 1.0The total of the relative abundances must be1.0 (or very close.)

Weighted Average Because the data classes occur withdifferent frequencies, , we cannotsimply add the values of the dataclass together. We must give each data class aweight. . (Thus the term ‘weighted’average.) Weighting each class eliminates theneed for the simple average we usedearlier.

Page 1 and 2: Weighted AveragesHow relative atomi
Page 3 and 4: An Example Let’s s imagine a clas
Page 5 and 6: Weighted Average The Greek letter s
Page 7: Weighted Average There was only 1 s
Page 11: Why bother? At this point you may b
Page 14 and 15: Relative Atomic Mass Actually, we h
Page 16 and 17: An Example Problem To get chlorine
Page 18: Conclusion By rounding an element

Weighted Averages and Relative Atomic Mass PowerPoint

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