Weighted Averages and Relative Atomic Mass PowerPoint

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Relative Atomic Mass Actually, we have no choice but tocalculate average atomic mass in thisway. Atoms are to small to even see, let alonecount individually. So we can’t t calculate asimple average (like you did with theBeanium Lab) even if we wanted to. And, a small amount of matter contains ahuge number of atoms, so relativeabundances or % frequencies are the onlypractical way to go about it.
An Example Problem Chlorine has 2 naturally occurringisotopes: Cl-35 (accurate mass34.968amu) and Cl-37 (accuratemass 36.965amu). Cl-35 abundance is 75.77%(RA = 0.7577). Cl-37 abundance is 24.23%(RA = 0.2423). We cannot simply add 35 and 37 toget an average of 36.
Page 1 and 2: Weighted AveragesHow relative atomi
Page 3 and 4: An Example Let’s s imagine a clas
Page 5 and 6: Weighted Average The Greek letter s
Page 7 and 8: Weighted Average There was only 1 s
Page 9 and 10: Weighted Average Because the data c
Page 11: Why bother? At this point you may b
Page 16 and 17: An Example Problem To get chlorine
Page 18: Conclusion By rounding an element

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