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AID - Franklin Electric Europa

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Cooling flow =Quantity dischargeRing spaceV =Q · 353,68(D 2 W - D 2 M )D W =Q · 353,68V+ D M2PUMPV [m/s] = cooling flow3Q [m /h] = volumetric delivery of pump at operating pointD W [mm] = inner diameter of well pipe/cooling sleeve= outer diameter of motorD M [mm]V=Example:- Flow: 50 m 3 /h- Motor: 6“ Encapsulated (D M = 0,137m)- Well diameter: 0,3m- Is the minimum cooling flow of 16 cm/sguaranted?50 m 3 /h · 353,68(300mm 2 – 137mm 2 )MOTORD MThe flow is 0,248 m/s or 24,8 cm/sThe minimum cooling flow of 16 cm/s is guaranted;in fact it’s even higher than needed!D W

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