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Abstract Algebra Theory and Applications - Computer Science ...

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224 CHAPTER 13 THE SYLOW THEOREMSpower of p. Each P -conjugacy class contributes a positive power of p toward|P| except the equivalence class {P }. Since |P| is the sum of positive powersof p <strong>and</strong> 1, |P| ≡ 1 (mod p).Now suppose that G acts on P by conjugation. Since all Sylow p-subgroups are conjugate, there can be only one orbit under this action.For P ∈ P,|P| = |orbit of P| = [G : N(P )].But [G : N(P )] is a divisor of |G|; consequently, the number of Sylowp-subgroups of a finite group must divide the order of the group. □Historical NotePeter Ludvig Mejdell Sylow was born in 1832 in Christiania, Norway (now Oslo).After attending Christiania University, Sylow taught high school. In 1862 he obtaineda temporary appointment at Christiania University. Even though his appointmentwas relatively brief, he influenced students such as Sophus Lie (1842–1899). Sylow had a chance at a permanent chair in 1869, but failed to obtain theappointment. In 1872, he published a 10-page paper presenting the theorems thatnow bear his name. Later Lie <strong>and</strong> Sylow collaborated on a new edition of Abel’sworks. In 1898, a chair at Christiania University was finally created for Sylowthrough the efforts of his student <strong>and</strong> colleague Lie. Sylow died in 1918.13.2 Examples <strong>and</strong> <strong>Applications</strong>Example 2. Using the Sylow Theorems, we can determine that A 5 hassubgroups of orders 2, 3, 4, <strong>and</strong> 5. The Sylow p-subgroups of A 5 have orders3, 4, <strong>and</strong> 5. The Third Sylow Theorem tells us exactly how many Sylowp-subgroups A 5 has. Since the number of Sylow 5-subgroups must divide60 <strong>and</strong> also be congruent to 1 (mod 5), there are either one or six Sylow5-subgroups in A 5 . All Sylow 5-subgroups are conjugate. If there were onlya single Sylow 5-subgroup, it would be conjugate to itself; that is, it wouldbe a normal subgroup of A 5 . Since A 5 has no normal subgroups, this isimpossible; hence, we have determined that there are exactly six distinctSylow 5-subgroups of A 5 .The Sylow Theorems allow us to prove many useful results about finitegroups. By using them, we can often conclude a great deal about groups ofa particular order if certain hypotheses are satisfied.Theorem 13.8 If p <strong>and</strong> q are distinct primes with p < q, then every groupG of order pq has a single subgroup of order q <strong>and</strong> this subgroup is normal

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