1.(lOpts) A car travels 20 kilometers at an average speed of 80 km/h ...

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12. (5pts) What is the speed of the stone just before it hits the cliff?(a) zero(b) 9.8 m/s(c) 55 m/s(d) 67 m/s(e) 38 m/s13. (5pts) An astronaut on the space station whirls a 0.5 kg mass attached to a string in acircle of radius 1.6 m. If the speed of the mass is 8 mIs, what is the tension in the string?(a) 64 N(b) 32 N(c) 20 N(d) 4.9 N(e) none of the above14. (5pts) Two forces are applied to a 2 kg object floating out in space. One force has amagnitude of 20 N and the other has magnitude of 30 N. Which of the followingrepresent the minimum and maximum of the possible acceleration that the object canhave, depending on the relative directions of the two forces? (consider magnitudes only)(a) 0.0 m/S2, 15 m/s2(b) 0.0 m/S2, 10 m/s2(c) 2.1 m/S2, 4.4 m/s2(d) 5.0 m/S2, 25.0 m/s2(e) 0.0 m/S2, 8.3 m/s2
2axt 1 2Units:1m = 39.4in = 3.28ft1atm = 1.013x 105PaFormula Sheet for LSD Physics 2101 Exams, Fall '09Imi = 5280ft1cal = 4.187JConstants:g = 9.8m/s2G = 6.67xl0-ll m3/(kg·s2)Earth-Sun distance = 1.50X 1011mk = 1.38 X 10-23 J /KProperties of H20:Density:Specific heat:Heats of transformation:Equations of Constant Acceleration:linear equation tmissing() w0:Wo- ()oalong xX-Xo missing Vox ax Vx tX - Xo -even; + vx)tX - Xo = vxt - -axt22 v~X -= Xo v~x = + ven;t 2ax(x + -axt - xo)Pwaterlmin = 60s,1day = 24hT = (~o~)Tc + 273.15KREarth = 6.37 X 106 mRMoon = 1.74 X 106 mMSun = 1.99xl03o kgR = 8.31J/(mol·K)= 1000 kg/m3MEarth = 5.98xl024kgMMoon = 7.36x 1022 kgEarth-Moon distance = 3.82x108 mAvogadro's # = 6.02 xI023partic1es/molCwater = 4187 J/(kg K) Cke = 2220 J/(kg K)Lvaporization = 2.256 X 106 J/kg Lfusion = 3.33 X 105 J /kg-b± Vb2 - 4acQuadratic formula: for ax2 + bx + c = 0, Xl 2 = -------. ' 2aMagnitude of a vector: lal = Ja; + a~ +a;Dot Product: a· 6 = axbx + ayby + azbz = lal161 cos(¢) (if; is smaller angle between ii and b)Cross Product: a x 6 = (aybz - azby)i + (azbx - axbz)j + (axby - aybx)k, la x 61 = lallbl sin(¢)rotational equationw = Wo + O:xt1 2() - ()o = wot + -o:t2w2 = w~ + 2o:«() - ()o)1() - ()o = -Cwo + w)t2 1() - ()o = wt - -o:t221Vector Equations of Motion for Constant Acceleration: .~=ro+ vot + -at2, v = Vo+ at2Projectile Motion: (with + direction pointing up from Earth)1 2X - Xo = (vocos()o)t y - Yo = (vo sin ()o)t - -gt2Vx = Vo cos ()o vy = (vo sin ()o) - gtgx2v~ = (vo sin ()0)2 - 2g(y - Yo) y = (tan ()o)x - 2( Vo cos ()o )2Newton's Second Law: 2:F = mamv2Uniform circular motion: Fe = -- = maer27rrT=-VForce of Friction: Static: Is::; Is,rnax = J.LsFN, Kinetic: Ik = J.LkFNElastic (Spring) Force: Hooke's Law F = -kx (k = spring (force) constant)1Kinetic Energy (nonrelativistic): Translational K = -mv22Work:v~ ·sin(2()0)R=----9-- W = F· d (constant force), W = lxf Xi F(x)dx (variable I-D force), W = Jri rf F(r). - dr (variable 3-D force)Work - Kinetic Energy Theorem: W = t!&.K= K f - Ki where W is the net work
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1.(lOpts) A car travels 20 kilometers at an average speed of 80 km/h ...

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