บทที่ 2 รากของสมการตัวแปรเดียว

11/6/2012Bisection Method: Example11f x 1 < 0 f a f x 1 > 0 x 1 , b = 0.5,1a = x 1 = 0.5x 1x 2 , x 3 , x 4 , …i a b f(a) f(b) xi f(xi) |x(i)-x(i-1)|1 0.000000000 1.000000000 -2.000000000 2.436563657 0.500000000 -0.2025574592 0.500000000 1.000000000 -0.202557459 2.436563657 0.750000000 0.984000033 0.2500000003 0.500000000 0.750000000 -0.202557459 0.984000033 0.625000000 0.361491915 0.1250000004 0.500000000 0.625000000 -0.202557459 0.361491915 0.562500000 0.072609314 0.0625000005 0.500000000 0.562500000 -0.202557459 0.072609314 0.531250000 -0.066635396 0.0312500006 0.531250000 0.562500000 -0.066635396 0.072609314 0.546875000 0.002565113 0.0156250007 0.531250000 0.546875000 -0.066635396 0.002565113 0.539062500 -0.032139781 0.0078125008 0.539062500 0.546875000 -0.032139781 0.002565113 0.542968750 -0.014813596 0.0039062509 0.542968750 0.546875000 -0.014813596 0.002565113 0.544921875 -0.006130820 0.00195312510 0.544921875 0.546875000 -0.006130820 0.002565113 0.545898438 -0.001784500 0.00097656311 0.545898438 0.546875000 -0.001784500 0.002565113 0.546386719 0.000389895 0.00048828112 0.545898438 0.546386719 -0.001784500 0.000389895 0.546142578 -0.000697405 0.00024414113 0.546142578 0.546386719 -0.000697405 0.000389895 0.546264648 -0.000153781 0.00012207014 0.546264648 0.546386719 -0.000153781 0.000389895 0.546325684 0.000118051 0.00006103515 0.546264648 0.546325684 -0.000153781 0.000118051 0.546295166 -0.000017867 0.000030518Bisection Method: Example12x 15 = 0.546295166f x 15 = 0.179 × 10 −415x 15 − x 14 = 0.305 × 10 −4x i − x i−1 x 15 − x 14 = 0.305 ×10 −4 ≤ 0.5 × 10 −3x 15 = 0.546295166x 15 = 0.5463 D.P.5