Drag on a Sphere

1.5× 10 ≤Re ≤ 1.2×103 4For ,log C =− 2.4571+ 2.5558w− 0.9295w+ 0.1049w10D2 31.2× 10 ≤Re ≤ 4.4×104 4For ,log C =− 1.9181+ 0.6370w−0.0636w10D24.4× 10 ≤Re ≤ 3.38×104 5For ,5 5× ≤ ≤ × CD= 29.78 − 5.33.38 10 Re 4 10For ,5 6× ≤ ≤ CD= 0.1w−0.494 10 Re 10For ,log C =− 4.3390 + 1.5809w−0.1546w10Dw2610 < ReFor ,C D8×10= 0.19 −Re4You can use the above equations to evaluate the drag coefficient when needed.Terminal Settling VelocityIf you want to calculate the terminal settling velocity of a sphere, you will find that thisvelocity appears in both the drag coefficient and in the Reynolds number. Therefore, youmust perform an iterative calculation to find the answer. To avoid doing this, Clift,Grace, and Weber also provide results that permit the direct calculation of the terminalsettling velocity. Recall that for terminal settling, the drag on the sphere is equal to itsnet weight, which is the weight minus the buoyant force on the sphere. We define theReynolds number in the same way as before, but with the understanding that it nowV = V terminalapplies with . A new dimensionless groupD Dis introducedin which the terminal settling velocity does not appear. Therefore you can calculate thisgroup and use the equations given below to calculate the value of the Reynolds numbercorresponding to a given value of ND. From the Reynolds number, you canimmediately evaluate the terminal settling velocity. In the equations, W = log10ND.N= CRe2N ≤73; Re ≤2.37For ,DNDRe = − 1.7569× 10 N + 6.9252× 10 N − 2.3027× 10 N24−4 2 −7 3 −10 4D D D2