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Trigonometric functions and circular measure - the Australian ...

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A guide for teachers – Years 11 <strong>and</strong> 12 • {19}Exercise 5A triangle has two sides of length 5 cm <strong>and</strong> 4 cm containing an angle θ. Its area is 5 cm 2 .Find <strong>the</strong> two possible (exact) values of θ <strong>and</strong> draw <strong>the</strong> two triangles that satisfy <strong>the</strong> giveninformation.Exercise 6Write down two different expressions for <strong>the</strong> area of a triangle ABC <strong>and</strong> derive <strong>the</strong> sinerule from <strong>the</strong>m.<strong>Trigonometric</strong> identitiesThe Pythagorean identityThere are many important relationships between <strong>the</strong> trigonometric <strong>functions</strong> which areof great use, especially in calculus. The most fundamental of <strong>the</strong>se is <strong>the</strong> Pythagoreanidentity. For acute angles, this is easily proven from <strong>the</strong> following triangle ABC withhypotenuse of unit length.B1sin θAθcos θCWith ∠B AC = θ, we see that AC = cosθ <strong>and</strong> BC = sinθ. Hence Pythagoras’ <strong>the</strong>orem tellsus thatcos 2 θ + sin 2 θ = 1.This formula holds for all angles, since every angle can be related to an angle in <strong>the</strong> firstquadrant whose sines <strong>and</strong> cosines differ only by a sign, which is dealt with by squaring.Dividing this equation respectively by cos 2 θ <strong>and</strong> by sin 2 θ, we obtain1 + tan 2 θ = sec 2 θ <strong>and</strong> cot 2 θ + 1 = cosec 2 θ.From <strong>the</strong>se st<strong>and</strong>ard identities, we can prove a variety of results.

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