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Trigonometric functions and circular measure - the Australian ...

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A guide for teachers – Years 11 <strong>and</strong> 12 • {31}Thus, measuring <strong>the</strong> angles in radians,l2πr = θ2π=⇒ l = r θ.It should be stressed again that, to use this formula, we require <strong>the</strong> angle to be in radians.ExampleIn a circle of radius 12 cm, find <strong>the</strong> length of an arc subtending an angle of 60 ◦ at <strong>the</strong>centre.O60 º12 cmSolutionWith r = 12 <strong>and</strong> θ = 60 ◦ = π , we have3l = 12 × π = 4π ≈ 12.57 cm.3It is often best to leave your answer in terms of π unless o<strong>the</strong>rwise stated.We use <strong>the</strong> same ratio idea to obtain <strong>the</strong> area of a sector in a circle of radius r containingan angle θ at <strong>the</strong> centre. The ratio of <strong>the</strong> area A of <strong>the</strong> sector to <strong>the</strong> total area of <strong>the</strong> circleequals <strong>the</strong> ratio of <strong>the</strong> angle in <strong>the</strong> sector to one revolution.Thus, with angles <strong>measure</strong>d in radians,Aπr 2 = θ2π=⇒ A = 1 2 r 2 θ.The arc length <strong>and</strong> sector area formulas given above should be committed to memory.

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