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Method of Joints Worksheet

Method of Joints Worksheet

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<strong>Method</strong> <strong>of</strong> <strong>Joints</strong>Let’s begin by calculating the forces in each member <strong>of</strong> the truss. We will assumea load <strong>of</strong> 20N applied to the center <strong>of</strong> the bridge (this results in a 10N load appliedto each <strong>of</strong> the two trusses.) For our calculations we will be working with only one<strong>of</strong> the parallel trusses. Since the bridge and loading are both symmetrical, thereactions at both ends (A and E) <strong>of</strong> the truss are equal to half <strong>of</strong> the applied load.10 NB C D12.5 cmAHFEG10 cm 10 cm 10 cm 10 cmStarting with a free-body diagram at Joint A:F ABA5 NαF AHFree-body Diagram atJoint A


Now that we have done the calculations, is member AH in tension orcompression? ___________________What about member AB? __________________________________Our final answer should indicate whether the members are in tension orcompression.F AB = 6.4 N (C)F AH = 4.0 N (T)Now lets move on to Joint H and determine what direction the force F AH ispointing.F AHA HF AHHFrom this, we can see that the force from member AH should be pointing to theleft at pin H.The free-body diagram for Joint H is shown next.F BHGH AHFxF AH H F GHFree-body Diagram atJoint H F F Fy F GH =FBHF BH =Is F GH in tension or compression? __________________At joint H, we notice that F BH equals 0 N. This is called a zero-force member.Zero-force members are important in trusses for several reasons.


What are some <strong>of</strong> the reasons you can think <strong>of</strong>?Now let’s analyze Joint B. First, draw the free-body diagram in the space below.


ααF BCFx F cos( ) F cos( ) F 0AB BG BC ( ) FBG FBC 0 F AB6.4 NF BH0NF BGFyFBGsubstitute F into the second equation aboveBGFBCCheck for tension or compressionF BC =F BG =The only member left to solve for is CG. We can solve for it at joint C.Draw the free-body diagram and solve for F CG .F CG =


Now let’s calculate the expected failure load and location.Consider member AB, is this member in tension or compression? _____________From the data sheet, what is the expected failure load <strong>of</strong> member AB? _________From the method <strong>of</strong> joints analysis, what was the internal member force inmember AB for the design load <strong>of</strong> 10N? ____________In order to calculate the Factor <strong>of</strong> Safety (F.S.) for member AB use the equationbelow.Expected Failure LoadFS . . Internal Member Force___________________MemberInternal MemberForce (Newtons)Expected Failure Load(Newtons)F.S.AB, DE 6.4 (C) 56.8 8.9BC, CD8.0 (C)AH, EF 4.0 (T) 23.5* x 2 11.8BG, DG6.4 (T)GH, FG4.0 (T)CG10 (C)BH, DF 0 NA NA*Strength <strong>of</strong> tension members was experimentally determined to be 23.5N.


Where do you expect the truss to fail? ______________Calculate the expected failure load for the bridge:(F.S) x (number <strong>of</strong> parallel trusses) x (number <strong>of</strong> members at failure location) x (10 N) = _________Maximum load actually held by the bridge: _________________Member that failed: ______________

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