12.07.2015 Views

Normed versus topological groups: Dichotomy and duality

Normed versus topological groups: Dichotomy and duality

Normed versus topological groups: Dichotomy and duality

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

40 N. H. Bingham <strong>and</strong> A. J. OstaszewskiRemark. To see the need for the refinement norm in verifying continuity of compositionin H(X), we work with metrics <strong>and</strong> recall the permutation metric d X g (x, y) :=d X (g(x), g(y)). Recall also that the metric defined by the norm ‖f‖ g is the supremummetric ˆd g on H(X) arising from d g on X. Indeedd g (h ′ , h) = ‖h ′ h −1 ‖ g = sup z d X (gh ′ h −1 g −1 (z), z) = sup x d X (g(h ′ (x)), g(h(x)))= sup x d X g (h ′ (x)), h(x)).Since, as in Proposition 2.13,ˆd g (F 1 G 1 , F G) ≤ ˆd g (F 1 , F ) + ˆd gF (G 1 , G) ≤ ˆd ∞ (F 1 , F ) + ˆd ∞ (G 1 , G),we may conclude thatˆd ∞ (F 1 G 1 , F G) ≤ ˆd ∞ (F 1 , F ) + ˆd ∞ (G 1 , G).This reconfirms that composition is continuous. When g = e, the term ˆd F arises above<strong>and</strong> places conditions on how ‘uniformly’ close G 1 needs to be to G (as in Th. 3.13).For these reasons we find ourselves mostly concerned with H u (X).3.2. Lipschitz-normed <strong>groups</strong>. Below we weaken the Klee property, characterizedby the condition ‖gxg −1 ‖ ≤ ‖x‖, by considering instead the existence of a real-valuedfunction g → M g such that‖gxg −1 ‖ ≤ M g ‖x‖, for all x.This will be of use in the development of <strong>duality</strong> in Section 12 <strong>and</strong> partly in the considerationof the oscillation of a normed group in Section 3.3.Remark. Under these circumstances, on writing xy −1 for x <strong>and</strong> with d X the rightinvariantmetric defined by the norm, one hasd X (gxg −1 , gyg −1 ) = d X (gx, gy) ≤ M g d X (x, y),so that the inner-automorphism γ g is uniformly continuous (<strong>and</strong> a homeomorphism).Moreover, M g is related to the Lipschitz-1 norms ‖g‖ 1 <strong>and</strong> ‖γ g ‖ 1 , whered X (gx, gy)‖g‖ 1 := sup x≠yd X (x, y) , <strong>and</strong> ‖γ d X (gxg −1 , gyg −1 )g‖ 1 := sup x≠yd X ,(x, y)cf. [Ru, Ch. I, Exercise 22]. This motivates the following terminology.Definitions. 1. Say that an automorphism f : G → G of a normed group has theLipschitz property if there is M > 0 such that‖f(x)‖ ≤ M‖x‖, for all x ∈ G.(Lip)2. Say that a group-norm has the Lipschitz property , or that the group is Lipschitznormed,if each continuous automorphism has the Lipschitz property under the groupnorm.Definitions. 1. Recall from the definitions of Section 2 that a group G is infinitelydivisible if for each x ∈ G <strong>and</strong> n ∈ N there is some ξ ∈ G with x = ξ n . We may writeξ = x 1/n (without implying uniqueness).

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!