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Delta Function - Gauge-institute.org

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<strong>Gauge</strong> Institute Journal, Volume 8, No.2, May 2012H. Vic Dannonξ=∞−ikξ∫ δξ () e dξ=1.ξ=−∞Substituting this representation of 1 intoδ( x)k =∞1 ikx= e2π∫ dk ,k =−∞k =∞ ⎛ ξ=∞⎞1−ikξikxδ( x) = δ( ξ)e dξ e dk2π.k =−∞ ⎜⎝ξ=−∞⎠⎟∫ ∫ x =∞5.6 The Hyper-real f ( x) ≡ 1, does not satisfy ∫ fx ( ) dx

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