slides - Friedrich-Schiller-Universität Jena

a textbook example (2)
for m = 1 to c
x m (1) = 0;
for i = 2 to n-1
x m (i) = 1.0 – x (m-1) (i) + .5 * ( x (m-1) (i-1)+x (m-1) (i+1) );
x m (n) = 0;
for m = 1 to c
y(1) = 0;
for i = 2 to n-1
y(i) = 1.0 – x(i) + .5 * ( x(i-1)+x(i+1) );
y(n) = 0;
swap(y, x);
components
change storage: x,y