6-3 Solving Proportions notes
6-3 Solving Proportions notes
6-3 Solving Proportions notes
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Integrated ISection 6-3 <strong>Solving</strong> <strong>Proportions</strong>Example 2Solve 19 x=4 8Solution19⋅ 8 = 4x152 = 4x152= x4x = 38Example 33000 150Solve = [Do on your own]x 3Solution3000⋅ 3 = 150x9000 = 150x9000x150x = 60Using proportions to solve problemsWe can use proportions to solve for an unknown in situations with steady rates.Example 4A work crew lays 0.5 miles of new road in 1 week. At this rate, how long will it take to lay 3miles of new road?SolutionSince the rates for laying 0.5 miles and 3 miles are the same, a proportion can be used.Let t = the number of weeks it takes to lay 3 miles of road.0.5 3 miles miles= ← =1 t weeks weeks.5t= 3⋅1t = 3(2)t = 6It will take 6 weeks to lay 3 miles of new road.6-3 <strong>Solving</strong> <strong>Proportions</strong>
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