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Integrated ISection 6-3 Solving ProportionsExample 2Solve 19 x=4 8Solution19⋅ 8 = 4x152 = 4x152= x4x = 38Example 33000 150Solve = [Do on your own]x 3Solution3000⋅ 3 = 150x9000 = 150x9000x150x = 60Using proportions to solve problemsWe can use proportions to solve for an unknown in situations with steady rates.Example 4A work crew lays 0.5 miles of new road in 1 week. At this rate, how long will it take to lay 3miles of new road?SolutionSince the rates for laying 0.5 miles and 3 miles are the same, a proportion can be used.Let t = the number of weeks it takes to lay 3 miles of road.0.5 3 miles miles= ← =1 t weeks weeks.5t= 3⋅1t = 3(2)t = 6It will take 6 weeks to lay 3 miles of new road.6-3 Solving Proportions
Integrated ISection 6-3 Solving ProportionsExample 5Three grams of oxygen unite with 24 grams of hydrogen to form water. How many grams ofoxygen unite with 1 kg of hydrogen?SolutionLet x = the number of gramsconvert 1 kg to grams….1 kg = 1000gOxygen = OxygenHydrogen Hydrogen3gxg=24g1000g3000 = 24x3000= x24x = 125It will take 125 grams.Using proportions to find percentagesUse the following proportion to solve for percentages… Let x = percentageis = xof 100Example 6What percent of 20 is 15?SolutionLet x = the percentage15 = x20 100 20 ⋅ x = 15 ⋅ 10020x = 1500x = 75%Example 76 is what percent of 80?SolutionLet x = the percentage6 = x80 100 6 ⋅ 100 = 80 ⋅ x600 = 80xx = 7.5%6-3 Solving Proportions
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6-3 Solving Proportions notes

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