Analysis of a two-phase induction motor using dynamic model ...

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As. J. Energy Env. 2010, 11(01), 48-59 53Figure 6. Implemented Simulink model as proposed in this paper.Simulation ResultsIn this section, some simulation results showing excellent performance of the proposed systemare presented. The simulation model has been developed in Matlab/Simulink environment. Theparameters of the asymmetrical two-phase induction motor are then calculated from shortcircuit and no-load measurements. Throughout the main and auxiliary winding resistances aremeasured using DC tests, while the other parameters are estimated using the stand-still andsynchronous speed tests [1]. The motor parameters are tabulated in Table 1 and the ratings are110 V, 60 Hz, 1/4 HP, and four-pole [2]. In all simulated cases, the load torque is fixed at1.0096 Nm.Table 1. Two-phase induction motor parametersRsα= 7.14 Ω Lsα= 0.2549 H Lmα= 0.2464 HRsβ= 2.02 Ω Lsβ= 0.1846 H Lmβ= 0.1772 HRrα= 5.74 Ω Lrα= 0.2542 H J = 2.92× 10 −3 kg-m 2Rrβ= 4.12 Ω Lrβ= 0.1828 H a = 1.18The simulation results for the first method, which uses dynamic modelling, is shown in Fig. 7.In Fig. 7 (a), the main and auxiliary supply voltage are identical in amplitude at 60 Hz and twophase quadrature (sine and cosine wave forms) voltages were selected according to vaux.= avmain[6]. The supply voltage vaux.was fixed at 1.18v mainsince the winding turn ratio a was estimatedto be approximately 1.18. The simulation results of the dynamic response under no-load isshown in Fig. 7 (b) and (d). It can be seen that the stator and rotor currents decrease intosteady-state. At zoom pictures the stator and rotor currents. It can be seen that the stator androtor currents is well quadrature shown in Figs 7 (c) and (e). As a result, in Figs. 7 (f)-(g) it isseen that the electromagnetic torque response is generated in transient and steady-state androtor speed is constant at 1800 rpm.
As. J. Energy Env. 2010, 11(01), 48-59 54(a)(b)i s,main(c)i s,aux.(d)i r,aux.i r,main(e)(f)(g)Figure 7. Simulation results of the main and auxiliary two-phase induction motor (v main =110V rms and v aux. = a*110V rms ) at no-load condition.(a) supply voltage (b) stator current (c) stator current at zoom (d) rotor current (e) rotor current at zoom (f) electromagnetictorque and (g) rotor speed.
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