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The Heisenberg Antiferromagnet and the Lanczos Algorithm Abstract

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BSc Final Year Report - Mat<strong>the</strong>w HolmesModelling a 1D Spin Chain<strong>The</strong> Spin Chain HamiltonianFor a chain of N spins, <strong>the</strong> Hamiltonian is an x square matrix, given by Eq. (8) [1], where henceforth=2 N , <strong>the</strong> number of basis vectors (spin configurations), .H ψ H ˆ ψ ; (8)k ' k=zk 'zkTo obtain <strong>the</strong> Hamiltonian we must choose a model on which to base <strong>the</strong> summation of Eq. (4). <strong>The</strong>reare two general chain topologies to follow, open or closed [20,5]. We follow <strong>the</strong> closed topology, Eq.(9) [4], modelling <strong>the</strong> chain as a ring.N 1= − ˆ + Hˆ>HH (9)< i,ji,jN ,1Thus, for an N=5 chain say, with an initial state 1 =| 1 2 3 4 5 >, we cycle through <strong>the</strong> basis, actingwith in each case. At <strong>the</strong> chain's end, when i=N, we set j=1, <strong>and</strong> consider <strong>the</strong> interaction betweenend states. <strong>The</strong> spinors are not eigenvectors of x or y , so that H contains off-diagonal elements <strong>and</strong>must be diagonalised to find <strong>the</strong> eigenvalues.Ladder Operators<strong>The</strong> computation is simplified by substituting for x <strong>and</strong> y with terms containing <strong>the</strong> ladder operators + <strong>and</strong> - [5,2]. <strong>The</strong> elements of + <strong>and</strong> - may be guessed but are derived [20] for clarity. Consider +acting on s - (flipping <strong>the</strong> state) <strong>and</strong> on s + (destroying <strong>the</strong> state),ˆs 11 12 ( ↓) = = +S ; s 12 = 1, s 22 = 0 (10i)ˆ ss21ss122011 11 ( ↑) = = 0 s210010+S ; s 11 = s 21 = 0 (10ii)And, similarly for - , we obtain <strong>the</strong> ladder operators,+ 01− 00Ŝ = , = 0010From Eqs. (11) <strong>the</strong> spin operators are,( ˆ ˆ −ˆ S )+ + S( SˆSˆ−)S x =, Sˆ+ y −=2Ŝ (11)Substituting Eqs. (12) into Eq. (4), <strong>the</strong> <strong>Heisenberg</strong> Hamiltonian becomes,H = −J2iz z + − − +( Sˆ⋅ Sˆ+ Si⋅ Sj+ Si⋅ Sj)i j1 ˆ ˆ 1 ˆ ˆ22< i,j>. (12)ˆ . (13)<strong>The</strong> ladder operators are useful because <strong>the</strong>y can annihilate states [2], whereas x or y always flip <strong>the</strong>state. Polarised pairs are always destroyed by <strong>the</strong> ladder terms in Eq. (13), as shown in Eq. (14).5

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