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Mannheimer Manuskripte 177 gk-mp-9403/3 SOME CONCEPTS OF ...

Mannheimer Manuskripte 177 gk-mp-9403/3 SOME CONCEPTS OF ...

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6 MARTIN SCHLICHENMAIERother words: the closed sets are the algebraic sets. It is easy to verify the axioms for atopology:(1) K n and ∅ are open.(2) Finite intersections are open:U 1 ∩ U 2 = (K n \ V (I 1 )) ∩ (K n \ V (I 2 )) = K n \ (V (I 1 ) ∪ V (I 2 )) = K n \ V (I 1 ∩ I 2 ) .(3) Arbitrary unions are open:⋃i∈S(K n \ V (I i )) = K n \ ⋂ i∈SV (I i ) = K n \ V ( ∑ i∈S∑Here S is allowed to be an infinite index set. The ideali∈S I i consists of elementsin R n which are finite sums of elements belonging to different I i . The claim (1-3) easilyextends to this setting.I i ) .Let us study the affine line K. Here R 1 = K[X]. All ideals in K[X] are principalideals, i.e. generated by just one polynomial. The vanishing set of an ideal consists justof the finitely many zeros of this polynomial (if it is not identically zero). Conversely,for every set of finitely many points there is a polynomial vanishing exactly at thesepoints. Hence, beside the e<strong>mp</strong>ty-set and the whole line the algebraic sets are the setsof finitely many points. At this level there is already a new concept showing up. Thepolynomial assigned to a certain point set is not unique. For exa<strong>mp</strong>le it is possible toincrease the vanishing order of the polynomial at a certain zero without changing thevanishing set. It would be better to talk about point sets with multiplicities to get acloser correspondence to the polynomials. Additionally, if K is not algebraically closedthen there are non-trivial polynomials without any zero at all. These ideas we will takeup in later lectures. The other i<strong>mp</strong>ortant observation is that the open sets in K areeither e<strong>mp</strong>ty or dense. The latter says that the closure U of U, i.e. the smallest closedset which contains U is the whole space K. Assuming the whole space to be irreduciblethis is true in a more general context.Definition.(a) Let V be a closed set. V is called irreducible if for every deco<strong>mp</strong>osition V = V 1 ∪V 2with V 1 ,V 2 closed we have V 1 = V or V 2 = V .(b) An algebraic set which is irreducible is called a variety.Now let U be an open subset of an irreducible V . The two set V \ U and U areclosed and V = (V \ U) ∪ U. Hence, V has to be one of these sets. Hence, either U = ∅or V = U. As promised, this shows that every open subset of an irreducible space iseither e<strong>mp</strong>ty or dense. Note that this has nothing to do with our special situation. It

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