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Chapter 7 - Pearson

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112 <strong>Chapter</strong> 7 Applications of Trigonometry and Vectors24.2680 m25. 58.6 feet26. 11 feet long27. 13 meters tall28. 15.8 ft apart29. 53.2 ft30. C » 77.131. 115 km32. 2.4 miles33. 25 sq units34. The sides of the triangle measure 5, 10, and5 5 , which satisfy the converse of thePythagorean theorem: the area is 25 sq units35. a – b36. a + 3c37. 207 lb38. 209 newtons39. horizontal: 869; vertical: 41840. horizontal: 25 2; vertical: 25 241. magnitude: 15Angle: 126.9(θ lies in quadrant II)42. magnitude: 29Angle: 316.4(θ lies in quadrant IV)43. (a) i(b) 4i-2j(c) 11i-7j44. -9;142.145. The vectors are orthogonal.46. θ = 4547. 29 lb48. The force is 280 newtons (rounded) at an angleof 30.4° with the first boat.49. The pilot should fly on a bearing of 306°. Heractual speed is 524 mph.50. 4º51. 34 lb52. The resulting speed is 21 km per hr (rounded)and bearing is 118°53. Newton’s formula:Therefore,54. Mollweide’s formula:Therefore,a+ b cos ( A-B)=c sin C2+ 3 2+3=2 22- 3 2-3=2 21 2 1 2a- b cos ( A-B)=c cos C12 1 2Copyright © 2013 <strong>Pearson</strong> Education, Inc.

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