Chapter 7 - Pearson

Chapter 7 Review Exercises 11128. The ground speed is 198 mph. The bearing is186.5°.29. The ground speed is 230 km per hr. Thebearing is 167°.30. (a) v t » 56 mi sec.(b) 87 mi/sec.31. (a) R = 5 » 2.2 andA = 0.25+ 1 » 1.1About 2.2 in. of rain fell. The area of theopening of the rain gauge is about 1.12in. .3(b) V = 1.5; The volume of rain was 1.5 in. .32. R and A should be parallel and point inopposite directions.Summary Exercises on Applications ofTrigonometry and Vectors1. The lengths of the two wires are about 29 ftand 38 ft.2. 38.3 cm3. 5856 m apart.4. x » 15.8 ft per sec; 71.65. 42 lb6. 7200 ft above the ground7. (a) The speed of the wind is 10 mph(b) This represents a 30 mph wind in thedirection of v.(c) u represents a southeast wind of11.3 mph8. the groundspeed is about 380 mph; θ » 2; the bearing of the plane is 64°9. - 1£ sin A £ 1, the triangle cannot exist10. other angles can be 36 10 ¢ ; third side40.5 yd, or other angles can beChapter 714350¢;8º00¢ and third side 6.25 yds1. 63.7 m2. B » 25.03. B = 41.7°4. 70.9 mReview Exercises5. 54 20 ¢ or 12540¢6. A = 4930 ¢ .7. No; If you are given two angles of a triangle,then the third angle is known since the sum ofthe measures of the three angles is 180°. Sinceyou are also given one side, there will only beone triangle that will satisfy the conditions.8. No; the sum of a and b do not exceed c.9. a = 10, B = 30°(a) b = 10 sin 30° = 5. Also, any value of bgreater than or equal to 10 would yield aunique value for A.(b) Any value of b between 5 and 10, wouldyield two possible values for A.(c) If b is less than 5, then no value for A ispossible.10. A = 140º, a = 5, and b =7With these conditions, we can try to solve thetriangle with the law of sines.sin B sin A sin B sin140= = b a 7 57sin140sin B= » 0.89990265 B» 645Since A+ B= 140+ 64= 204> 180 , nosuch triangle exists.11. A » 19.87 or 19 52 ¢ .12. 173 ft13. 55.5 m14. B » 26.5 or 26 30 ¢ .15. 19cm16. 4717. B = 17.3 ; C = 137.5 ;c » 11.0 yd18. B 1 = 74.6 ; C 1 = 43.7 ; c 1 » 61.9 mC 2 = 12.9 ;c 2 » 20.0 m19. c » 18.65cm; B » 4550 ¢ ; A = 91 40¢20. B » 73.9 ;A » 47.7 ;C = 58.421.22.23.2153,600 m220.3 ft20.234 kmCopyright © 2013 Pearson Education, Inc.