Lecture Notes for Section 16.4 (Absolute Motion Analysis)
Lecture Notes for Section 16.4 (Absolute Motion Analysis)
Lecture Notes for Section 16.4 (Absolute Motion Analysis)
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EXAMPLE(continued)Solution:By geometry, s A = 2 cos qreferences AqABy differentiating with respect to time,v A = -2 w sin qUsing q = 60° and v A = 8 m/s and solving <strong>for</strong> w:w = 8/(-2 sin 60°) = - 4.62 rad/s(The negative sign means the rod rotates counterclockwise aspoint A goes to the right.) Differentiating v A and solving <strong>for</strong> a,a A = -2a sin q – 2w 2 cos q = 0a = - w 2 /tan q = -12.32 rad/s 2
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