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From Steiner formulas for cones to concentration of intrinsic volumes

From Steiner formulas for cones to concentration of intrinsic volumes

From Steiner formulas for cones to concentration of intrinsic volumes

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STEINER FORMULAS FOR CONES AND INTRINSIC VOLUMES 11Pro<strong>of</strong>. Let g 1 ∈ R d 1and g 2 ∈ R d 2be independent standard normal vec<strong>to</strong>rs. The direct product (g 1 , g 2 ) is astandard normal vec<strong>to</strong>r on R d 1+d 2. For each λ > 0, the definition (4.5) <strong>of</strong> the Wills functional gives(W C1 ×C 2(λ) = λ d 1+d 2 1 − λ2E exp · dist 2 ( ) )(g 1 , g 2 ),C 1 ×C 22(= λ d 1 1 − λ2) (E exp · dist 2 (g 1 ,C 1 ) · λ d 2 1 − λ2)E exp · dist 2 (g 2 ,C 2 ) = W C1 (λ) ·W C2 (λ).22The second identity follows from the fact that the squared distance <strong>to</strong> a product cone equals the sum <strong>of</strong> thesquared distances <strong>to</strong> the fac<strong>to</strong>rs; we have also invoked the independence <strong>of</strong> the standard normal vec<strong>to</strong>rs <strong>to</strong>split the expectation. Applying the relation (4.5) twice, we find thatW C1 ×C 2(λ) = W C1 (λ) ·W C2 (λ) =But (4.5) also shows that(d1∑λ i v i (C 1 )i=0)∑λ j v j (C 2 ))(d2j =0d 1 ∑+d 2W C1 ×C 2(λ) = λ k v k (C 1 ×C 2 ).k=0∑d 1 +d 2=k=0Comparing coefficients in these two polynomials, we arrive at the relation (5.1).λ k∑i+j =kv i (C 1 ) · v j (C 2 ).5.2. Concentration <strong>of</strong> the <strong>intrinsic</strong> <strong>volumes</strong> <strong>of</strong> a product cone. We can employ the probabilistic techniquesfrom Section 4 <strong>to</strong> collect in<strong>for</strong>mation about the <strong>intrinsic</strong> <strong>volumes</strong> <strong>of</strong> a product cone. Let C 1 ∈ C d1 and C 2 ∈ C d2be two <strong>cones</strong>, and consider independent random variables V C1 and V C2 whose distributions are given by the<strong>intrinsic</strong> <strong>volumes</strong> <strong>of</strong> C 1 and C 2 . In view <strong>of</strong> Corollary 5.1,v k (C 1 ×C 2 ) =∑v i (C 1 ) · v j (C 2 ) = P { V C1 +V C2 = k } <strong>for</strong> k = 0,1,2,...,d 1 + d 2 .i+j =kIn other words, the <strong>intrinsic</strong> volume random variable V C1 ×C 2<strong>of</strong> the product cone has the distributionV C1 ×C 2∼ V C1 +V C2 . (5.2)This observation allows us <strong>to</strong> compute the statistical dimension <strong>of</strong> the product cone:δ(C 1 ×C 2 ) = E [ V C1 ×C 2]= δ(C1 ) + δ(C 2 ). (5.3)Of course, we can also derive (5.3) directly from Proposition 4.3. A more interesting consequence is thefollowing expression <strong>for</strong> the variance <strong>of</strong> the <strong>intrinsic</strong> <strong>volumes</strong>:Var [ V C1 ×C 2]= Var[VC1 ] + Var[V C2 ] ≤ 2 [( δ(C 1 ) ∧ δ(C ◦ 1 )) + ( δ(C 2 ) ∧ δ(C ◦ 2 ))] . (5.4)The inequality follows from Theorem 4.5. With some additional ef<strong>for</strong>t, we can develop a <strong>concentration</strong> result<strong>for</strong> the <strong>intrinsic</strong> <strong>volumes</strong> <strong>of</strong> a product cone that matches the variance bound (5.4).Corollary 5.2 (Concentration <strong>of</strong> <strong>intrinsic</strong> <strong>volumes</strong> <strong>for</strong> a product cone). Let C 1 ∈ C d1 and C 2 ∈ C d2 be closedconvex <strong>cones</strong>. For each λ ≥ 0,P {∣ ∣ VC1 ×C 2− δ(C 1 ×C 2 ) ∣ (} −λ 2 )/4≥ λ ≤ 2 expσ 2 where σ 2 := ( δ(C 1 ) ∧ δ(C1 ◦ + λ/3)) + ( δ(C 2 ) ∧ δ(C2 ◦ )) .This represents a significant improvement over the simple tail bound from [ALMT13, Lem. 7.2]. A similarresult holds <strong>for</strong> any finite product C 1 × ··· ×C r <strong>of</strong> closed convex <strong>cones</strong>.Pro<strong>of</strong>. First, recall the numerical inequalitye 2ζ − 2ζ − 1≤2 1 − 2|ζ|/3ζ 2<strong>for</strong> |ζ| < 3 2 .This estimate allows us <strong>to</strong> package the two exponential moment bounds from Theorem 4.8 as(Ee ζ(V C ζ −δ(C)) 2 (δ(C) ∧ δ(C ◦ )))≤ exp<strong>for</strong> |ζ| < 31 − 2|ζ|/32 .Applying this bound twice, we learn that the exponential moments <strong>of</strong> the random variable V C1 ×C 2satisfy(Ee ζ(V C 1 ×C 2 −δ(C 1 ×C 2 )) = Ee ζ(V C 1 −δ(C 1 )) · Ee ζ(V C 2 −δ(C 2 )) ζ 2 σ 2 )≤ exp.1 − 2|ζ|/3□

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