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Student Notes To Accompany MS4214: STATISTICAL INFERENCE

Student Notes To Accompany MS4214: STATISTICAL INFERENCE

Student Notes To Accompany MS4214: STATISTICAL INFERENCE

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Suppose that a statistical model specifies that the data x has a probability distribu-<br />

tion f(x; θ) depending on a vector of m unknown parameters θ = (θ1, . . . , θm). In this<br />

case the likelihood function is a function of the m parameters θ1, . . . , θm and having<br />

observed the value of x is defined as L(θ) = f(x; θ) with ℓ(θ) = ln L(θ).<br />

The MLE of θ is a value ˆ θ for which L(θ), or equivalently ℓ(θ), attains its maximum<br />

value. For r = 1, . . . , m define Sr(θ) = ∂ℓ/∂θr. Then we can (usually) find the MLE<br />

ˆθ by solving the set of m simultaneous equations Sr(θ) = 0 for r = 1, . . . , m. The<br />

information matrix I(θ) is defined to be the m×m matrix whose (r, s) element is given<br />

by Irs where Irs = −∂ 2 ℓ/∂θr∂θs. The conditions for a value ˆ θ satisfying Sr( ˆ θ) = 0 for<br />

r = 1, . . . , m to be a MLE are that all the eigenvalues of the matrix I( ˆ θ) are positive.<br />

2.6 Newton-Raphsom Optimization<br />

Example 2.11 (Radioactive Scatter). A radioactive source emits particles intermittently<br />

and at various angles. Let X denote the cosine of the angle of emission. The angle<br />

of emission can range from 0 degrees to 180 degrees and so X takes values in [−1, 1].<br />

Assume that X has density<br />

1 + θx<br />

f(x|θ) =<br />

2<br />

for −1 ≤ x ≤ 1 where θ ∈ [−1, 1] is unknown. Suppose the data consist of n indepen-<br />

dently identically distributed measures of X yielding values x1, x2, ..., xn. Here<br />

L(θ) = 1<br />

2 n<br />

n�<br />

(1 + θxi)<br />

i=1<br />

l(θ) = −n ln [2] +<br />

S(θ) =<br />

I(θ) =<br />

n�<br />

i=1<br />

n�<br />

i=1<br />

xi<br />

1 + θxi<br />

n�<br />

ln [1 + θxi]<br />

i=1<br />

x 2 i<br />

(1 + θxi) 2<br />

Since I(θ) > 0 for all θ, the MLE may be found by solving the equation S(θ) = 0. It<br />

is not immediately obvious how to solve this equation.<br />

By Taylor’s Theorem we have<br />

0 = S( ˆ θ)<br />

= S(θ0) + ( ˆ θ − θ0)S ′ (θ0) + ( ˆ θ − θ0) 2 S ′′ (θ0)/2 + ....<br />

31

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