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AP Calculus

Calculus_SF_Theorem

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Special Focus: The Fundamental<br />

Theorem of <strong>Calculus</strong><br />

I want them to extend the ideas developed in the first two parts to each interval, thus<br />

getting the following answers to parts (c) and (d):<br />

“The minimum speed for 10 seconds is (30)(2)+(36)(2)+(40)(2)+(48)(2)+(54)(2)=416 feet.<br />

The maximum speed for 10 seconds is (36)(2)+(40)(2)+(48)(2)+(54)(2)+(60)(2)=476 feet.”<br />

I watch for those who might answer (c) with (3)(10)=300 feet and help them understand<br />

that even though this is a lower bound, it is not the greatest lower bound because they<br />

have not taken advantage of the data provided.<br />

As we go over parts (c) and (d), I also introduce them to important vocabulary by pointing<br />

out that the sums of products they have just computed are known as Riemann sums.<br />

Part (e) can sometimes give students trouble, but most will recognize that the exact<br />

distance is somewhere between 416 feet and 476 feet. This means that if you choose the<br />

lower estimate, 416, as an approximation, the maximum amount this approximation<br />

could differ from the exact distance is 60 feet.<br />

Part (f) responses sometimes amaze students and lead to a lively discussion. Although<br />

their answers will vary based on the choice of speeds each student selects, the difference<br />

between the best upper and lower estimates will always be ( 60 − 30)<br />

∆t, or 30 in this case<br />

since ∆t = 1.<br />

At this point I have the students tell me their new upper and lower estimates, and I<br />

record them on the blackboard. It becomes obvious that the speeds that were chosen<br />

make a difference in the upper and lower estimates; however, in every case the maximum<br />

error has been halved. Students observe that the amount of error can be made as small<br />

as desired by choosing ∆t sufficiently small. This is shown by expressing the error, E, as<br />

E ≤ v( 10) − v( 0)<br />

⋅ ∆t = 30⋅<br />

∆ t , which approaches 0 as ∆t → 0 .<br />

After working with this example, the students work with textbook problems involving<br />

data for a rate over equally spaced time intervals. I am not in a rush to get to problems<br />

in which we work with a function defined by a formula. I want the students to experience<br />

adding products of a rate and a small amount of the independent variable (in most<br />

examples, this is a small amount of time).<br />

<strong>AP</strong>® <strong>Calculus</strong>: 2006–2007 Workshop Materials 9

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