? ? B
Arus Bolak Balik - e-Learning Sekolah Menengah Kejuruan
Arus Bolak Balik - e-Learning Sekolah Menengah Kejuruan
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Z 3 = 0 + j 6 ? Z 8 = 4 – j 4 ?<br />
Z 4 = 2 + 10? Z 9 = 0 + j 2 ?<br />
Z 5 = 5 – j 12 ? Z 10 = 1 + j 7 ?<br />
V AB = 15 ? 0<br />
Tentukan: a). Z AD, b).V AD , dan c).Diagram fasor.<br />
Penyelesaian<br />
a. Z AD = Z AB + Z BC + Z CD<br />
Z AB = Z 1<br />
Z BC =<br />
Z<br />
2<br />
Z2Z<br />
3Z4<br />
? Z ? Z<br />
3<br />
4<br />
=<br />
(2 ?<br />
( 2 ? j3)(j6)(2) 36 ?<br />
?<br />
0 ? 2) ? j( ? 3 ? 6 ? 0)4 ? j3<br />
j24<br />
Z CD =<br />
(36 ? j24) (4 ? j3)<br />
4 ? 3<br />
=<br />
2 2<br />
(Z<br />
Z<br />
5<br />
5<br />
? Z<br />
? Z<br />
6<br />
6<br />
? Z<br />
? Z<br />
7<br />
7<br />
)(Z<br />
? Z<br />
8<br />
8<br />
? Z<br />
? Z<br />
9<br />
9<br />
? Z<br />
? Z<br />
? (5 ? 6 ? 8) ? J( ? 12 ? 3 _ 6) ?? (4 ? 0 ? 1) ? J( ? 4 ? 2 ? 7) ?<br />
=<br />
10<br />
10<br />
(5 ? 6 ? 8 ? 4 ? 0 ? 1) ? J( ? 12 ? 3 ? 6 ? 4 ? 2 ? 7)<br />
)<br />
=<br />
(19 ? j9)(5 ?<br />
(24 ? j4)<br />
j5)<br />
?<br />
(140 ?<br />
(24 ?<br />
j50)<br />
j4)<br />
(140)j50)(24 ?<br />
=<br />
2 2<br />
24 ? 4<br />
j4) 3560 ? j640<br />
?<br />
592<br />
= (6,014 + j 1,08)<br />
Z AD = (6 + J 8) + (2,88 – j 0,48) + (6,01 + j 1,08)<br />
= (14,89 + j 8,6) = 17,2 ? 30,01 o<br />
Modul.FIS.22 Arus Bolak-Balik 33
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