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BÀI TẬP TRẮC NGHIỆM HÓA ĐẠI CƯƠNG VÀ VÔ CƠ CẨM NANG DÙNG LUYỆN THI THPTQG CHẤT LƯỢNG CAO (COLOR BOOK)

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2, Br 2<br />

–<br />

(ClO – , BrO – ):<br />

Cl 2 + 2NaOH NaCl + NaClO + H 2 O<br />

Br 2 + 2KOH KBr + KBrO + H 2 O<br />

o<br />

), Cl 2 , Br 2<br />

3 – (ClO 3– , BrO 3– ):<br />

3Cl 2 + 6KOH<br />

o<br />

t<br />

5KCl + KClO 3 + 3H 2 O<br />

VD7: Cho 8,96 lít khí Cl 2<br />

nhiêu gam NaCl?<br />

nCl 2<br />

2 + 2NaOH NaCl + NaClO + H 2 O<br />

0, 4 (mol).<br />

n n<br />

NaCl Cl 2<br />

0, 4 (mol).<br />

NaCl = 58,5.0,4= 23,4 (gam).<br />

VD8 Cho 13<br />

o<br />

(A) 0,24 M. (B) 0,48 M.<br />

(C) 0,4 M. (D) 0,2 M.<br />

n 0,6 (mol); n 0,5 (mol).<br />

Cl2<br />

KCl<br />

2 + 6KOH t o<br />

5KCl + KClO 3 + 3H 2 O<br />

nCl<br />

n<br />

2 KCl<br />

Vì nên Cl 2<br />

3 5<br />

6 6<br />

n n .0,5 0,6 (mol).<br />

KOH KCl<br />

5 5<br />

0,6<br />

[KOH]= 0,24 M.<br />

2,5<br />

.<br />

6<br />

137

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