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BÀI TẬP TRẮC NGHIỆM HÓA ĐẠI CƯƠNG VÀ VÔ CƠ CẨM NANG DÙNG LUYỆN THI THPTQG CHẤT LƯỢNG CAO (COLOR BOOK)

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o<br />

t<br />

xO y 3xM + yAl 2 O 3<br />

2Al + Fe 2 O t o<br />

3 2Fe + Al 2 O 3<br />

8Al + 3Fe 3 O t o<br />

4 9Fe + 4Al 2 O 3<br />

2Al + 3FeO t o<br />

3Fe +Al 2 O 3<br />

2O 3<br />

(A) 16,6 gam.<br />

(C) 5,6 gam.<br />

(B) 11,2 gam.<br />

(D) 22,4 gam.<br />

n 0, 4 (mol); n 0,1 (mol).<br />

Al<br />

Fe2O3<br />

2O t o<br />

3 2Fe + Al 2 O 3 (1)<br />

n nFe2O3<br />

Vì:<br />

Al<br />

2O 3<br />

2 1<br />

nAl (p−)<br />

2nFe 2O 0,2 (mol) n<br />

3<br />

Al (d−)<br />

0, 4 0,2 0,2 (mol).<br />

n 2n 0,2 (mol).<br />

Fe (sinh ra)<br />

Fe2O3<br />

= 0,2.27 + 0,2.56 = 16,6 (gam).<br />

5<br />

322

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