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GIẢI BÀI TẬP SINH HỌC 9 NGUYỄN VĂN SANG VÀ NGUYỄN THỊ VÂN THƯ VIỆN TRƯỜNG THCS NGÔ THÌ NHẬM ĐÀ NẴNG

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PHAN I:<br />

DI TllUI/EN Uif lllEN 01<br />

Chuong 1.:<br />

cAc DJNH LU!T DI TRUYEN. CUA MENDEN<br />

A. LAI MQT CAP TINH TRANG - on·H LU!T DONG<br />

TINH VA DJNH U!T PI-IAN LI<br />

I. MOT SO KIEN THU'C CO' BAN<br />

L Tom tit ket qua phep lai m()t c«)p tinh tr,ng<br />

Menden tien hnh lai a nhung cp bo me thuan chting.<br />

Duoi day Ia ket qua thu duqc a m¢t so phep Iai :<br />

p Fi F2<br />

..<br />

Than cao x than thap Than cao 75% than cao : 25% than thap<br />

--·<br />

H.t mau vang x Hc;1t mau xanh Hc;it vang<br />

75% hc;1t vang : 25% hc;it xanh<br />

Hc;it tran x Hc;1t nhan Hc;tt tran 75% hc;tt tran : 25% hc;ll nhan<br />

--<br />

Tu ket qua cua cac phep lai neu tren va cua nhieu phep lai khac, Menden<br />

· rut ra ket lun chung, do la F I<br />

d6ng loc;lt xuat hi(:n tinh trc;lng cua m


F I<br />

lai voi nhau :<br />

F I<br />

: Aa (hoa hong) x Aa (hoa hong)<br />

GF 1<br />

: A,a<br />

F 2<br />

:<br />

A,a<br />

I AA : 2 Aa : 1 aa<br />

Kieu hinh : 1 hoa do : 2 hoa hong : 1 hoa trcing<br />

6. Cac SO' d6 lai c6 the gap khi lai mc)t c(ip tinh trng theo djnh lut Menden<br />

P: AA x AA P: AA x Aa<br />

GP: A A GP: A A, a<br />

F 1<br />

AA F 1<br />

: 1 M: 1 Aa<br />

:<br />

d6ng tinh tr(>i dong tinh tr(>i .<br />

·,<br />

_,<br />

( l tr(>i : I trung gian)<br />

--i-----,-----·-<br />

P: AA x aa P: Aa x Aa<br />

GP: A a GP: A, a A, a<br />

F 1<br />

Aa F 1<br />

IM:2Aa:laa<br />

:<br />

:<br />

d6ng tinh tr(>i<br />

3 tn)i : 1 ln<br />

(d6ng tinh trung gin) ( 1 tri : I ln d6ng tinh ln<br />

( I trung gian : I ln)<br />

Ghichu<br />

Cac ket qua v kieu hinh con lai duqc neu trong dau ngoc cu.a bang tren<br />

duqc ap dt,mg rieng cho truang hqp tfnh tr(>i khong hoan toan.<br />

7. Cac ki hiu thuong su di.mg<br />

P : the M bo mE:<br />

F : the he con lai<br />

(F : 1<br />

the M con lai thu nhat; F : 2<br />

the M con lai thu hai...)<br />

G : giao tu<br />

(GP: giao tu cu.a P; GF : 1<br />

giao tu cu.a F •••)<br />

1<br />

Dau nhan (x): chi SlJ lai giong<br />

cf': dIJC<br />

Q: cai<br />

aa<br />

II. CAC· DANG BAI TAP<br />

Ta thuang gp hai d,.mg bai tc}p, t9m gqi la bai to


d. Sa d6 lai tir P den F 2<br />

- Theo de bai, qui UO'C :<br />

HUONG DAN GIAI<br />

Gen A : qua trcm trqi khong hoan loan so VO'i gen a : qua daL<br />

Ta c6<br />

Kieu gen cua P<br />

• P c6 qua tron : AA<br />

• P c6 qua dai : aa<br />

So do lai P den F 2<br />

P: AA (tron) x<br />

GP: A<br />

F 1:<br />

AA : qua tron, aa : qua dai<br />

Aa : qua bau dl)C (tinh tr


' . .<br />

> Thi di! 2<br />

Giao phan giua cay, F xuat hi¢n ca h;;it tron va h;;it dai.<br />

I<br />

Biet h9t tron la tinh trc;1ng tr(>i hoan toan.<br />

Xac dinh bo m va lp so do lai trong moi truang hqp sau day .:<br />

a. Bo va m c6 cung kieu gen.<br />

b. Bo va m mang kieu gen khac nhau.<br />

HUONG DAN GIAI<br />

Theo de bai, qui UO'C:<br />

A : hc;1t tron, a : h9t dai<br />

Xet F I c6 hc;1t. dai la tinh ln, kieu gen (aa) .. Suy ra 2 cay bo va m deu t;;io<br />

duqc giao tu a, tuc c6 kieu gen Aa hoc}c aa.<br />

a. feu bo m{! c6 cimg kieu gen.:<br />

Bo va m deu 'mang Aa, tuc c6 'h


Minh hn<br />

aa<br />

a<br />

100% chin som (dong tinh)<br />

• P : Chin som khong thun chung x chin mu(>n<br />

Aa<br />

aa<br />

GP:<br />

A, a<br />

a<br />

F 1<br />

: Kieu gen 1 Aa : 1 aa<br />

Kieu hinh 1 chin som : 1 chin mu(m<br />

(Phan tinh 2 kieu hinh)<br />

b. So d6 lai P den F 2 :<br />

Cay P thuan chung chin som, kieu gen AA<br />

Cay P chin mu


So do lai:<br />

p : thuan chung than cao x thuan chung than thap<br />

aa<br />

AA<br />

GP: a<br />

A<br />

I F l :<br />

Aa<br />

Kieu hinh 100% than cao<br />

b. Cho F 1<br />

lai vai nhau:<br />

F t : Aa (than thap) x Aa (than thap)<br />

GF ; 1<br />

A,a<br />

A, a<br />

F : 1<br />

1 AA : 2 Aa : 1 aa<br />

Kieu hinh 3 than thap : 1 than cao<br />

c. Cho F 1<br />

lai phcin tich :<br />

F : 1<br />

Aa (than thap) x aa (than cao)<br />

GF 1<br />

: A,a<br />

a<br />

F : 2<br />

lAa: l·aa<br />

Kieu hinh 1 than thap : l_ than cao<br />

Bil 5 : Khi cho cac ciy F I<br />

giao phi:n voi nhau, nguoi ta thu duqc F 2<br />

co 450 ciy co htt den va 150 ciy co htt niu.<br />

a. Hay d11a vao m(>t djnh Iott di truyn nao do cu.a Menden d xac<br />

djnh tinh tr(>i, tinh ltn va ltp qui ooc gen.<br />

b. l.4p SO' do giao phi:n cu.a F 1<br />

•<br />

c. Stiy ra cl)p P di lai tto ra cac ciy F I<br />

noi tren va ltp sa do minh hqa.<br />

GIAI<br />

a. X


I<br />

Theo de bai, tong so to hqp giao tu tc;10 ra tu hai phep lai la 6. Ta co :<br />

6 to hqp = 4 to hqp +<br />

: . 2 t hqp . .<br />

= (2 giao tu x 2 giao tu) + (2 g1ao tu x 1 g1ao tu)<br />

• Ca the dt..rc tham gia vao hai phep lai. Suy ra ,<br />

ca the dt..rc tc;10 hai loc;1i giao<br />

tu tuc phai co kieu gen Aa, kieu hinh long xam.<br />

Trong hai ca the cai c6 m(>t ca the t9o hai lmii giao tu va m(>t ca the t90<br />

mc)t loc;1i gia0 tu.<br />

Theo de bai so loc;1i giao tu cua ca the cai thu nhat nhieu hon, suy ra :<br />

• Ca the cai thu nhat to hai loc;1i giao tu, tuc c6 kieu gen Aa, kieu hinh long<br />

xam.<br />

• Ca the cai thu hai ti;lO mf)t loc;1i giao tu, tuc c6 kieu gen AA (kieu hinh long ·<br />

xam) hoc aa (kieu hinh long den).<br />

b. So d6 cha m6i phep lai :<br />

* Phep lai giiia ca the dl!C vii cd the cai th(r nhat :<br />

p : dt..rc Aa (long xam) x cai Aa (long xam)<br />

GP: A,a<br />

A,a<br />

F 1 :<br />

1 AA: 2 Aa: 1 aa<br />

Kieu hinh 3 long xam : 1 long den<br />

* Phep lai gilia ca the dt..rc va ca the cai thu hai :<br />

Truong hc;,p I : neu ca the cai thu hai mag AA :<br />

p : dt..rc Aa (long xam} x cai M (long xam)<br />

GP: A,a<br />

A<br />

1 AA: I Aa<br />

1 .<br />

Kieu hinh I 00% long xam<br />

F '·<br />

- Truong hc;,p 2 : neu ca the cai thu hai mang aa :<br />

·"'p : dt..rc Aa (long xam) x cai aa (long den)<br />

GP: A,a<br />

a<br />

F : 1<br />

lAa laa<br />

Kieu hinh I long xam : 1 long den<br />

Bili 9 Lai giua' hai cay P ve m


Neu b6 mang kieu gen aa<br />

P : b6 aa (cao) x m Aa (thap)<br />

GP: a<br />

A,a<br />

F 1 : lAa:laa<br />

Kieu hinh 1 tam voe thap : 1 tarn voe cao<br />

Con trai duqc d cp la aa<br />

Bii 12: O' nguoi gen qui djnh d,ng toe nAm tren NST thuoog<br />

a. O' gia dinh thu nhat b6 va m du co toe xoan sinh duqc dua con<br />

gai c6 toe thAng.<br />

Hay giai thich de xac djnh tinlt tr,ng tr


. Xac dinh kieu gen cua cac ca. the :<br />

- 86 (1) va m (2) deu c6 long nau sin.h con (3) long trang<br />

==> Kieu gen so (;3) long trang la aa va b6 m deu lq.O duqc giao tu a. Vf>_y (1)<br />

va (2) long nau deu co kieu gen Aa.<br />

- Xet (3) x (5) sinh ra (6) :<br />

• (3) long trang mang aa lq.O giao tu a Cho COO la (6)<br />

• (6) c6 iong nau nMn a tu (3), nen (6) co kieu gen Aa va nMn giao tu A<br />

tu cs)<br />

• (5) long nau tq.o A cho con (6) ==> (5) mang kieu gen M hoi (A-). Suy ra ru6i F 1 long rnem mang lai chi tc;to duy nhat<br />

rn(>t loc;ti giao tu A, c6 kieu gen AA<br />

Sa do lai : F 1 : M (Jong mem) x aa (long cung)<br />

GF 1<br />

: A a<br />

F : 2<br />

Aa<br />

Kieu hinh I 00% long mem<br />

* Truong hgp 3 :<br />

F 1<br />

: long mem (A-) x long rnem (A-)<br />

F 2<br />

: 210 long rnem : 72 long cung<br />

F2 co ti I xap xi 3 long mem : l long cung, la ti J cua djnh lut phan tinh.<br />

Suy ra hai ruoi F 1<br />

deu co kieu gen di hqp Aa.<br />

Sa d6 lai : F 1<br />

: Aa (long rnem) x Aa (long mem)<br />

GF 1<br />

: A,a A,a<br />

F 2 :<br />

I M : 2 Aa : 1 aa<br />

Kieu hinh 3 long mem : I long cung<br />

b. Kieu gen kieu hinh cua P : .<br />

, Xet cac CO' the F I tu ket qua tren ta thay F xuat hin dli 3 kieu gen : M, Aa<br />

I<br />

va aa.<br />

i<br />

36<br />

37


To hqp l9i, suy ra kieu gen, kieu hinh cua bo, m la :<br />

Bo I A I O (mau A) va m 1 8 1 ° (mau B) hoc nguqc l


.-----------------·--<br />

- Lam the nao de chQn duqc ru6i } 1 co than xam la thuan 1thung de·<br />

mang lai ? Giai thich va minh hQa '!<br />

- ' Lp SO' do tu P den f 2<br />

cho phep lai tren.<br />

b. Neu cho Fl thu dUQ'C trong phep lai tren lai phan tich thi ket qua<br />

kieu hinh to ra se nhu the nao ?<br />

D.S:<br />

- Dung phep lai phan tich. (HQc sinh llf giai thich va minh hQa.)<br />

- p : BB x bb -- F I<br />

: Bb x Bb<br />

b. Ket qua : 1 than xam : 1 than den<br />

a.<br />

Bai 1 : Khi cho giao phoi giua ga trong long tr.ing voo ga mai long<br />

den du thuan chung, ngum ta thu dUQ'C cac con lai f I<br />

du co mau<br />

long xanh da troi.<br />

Biet gen qui djnh tinh trng m\m tren NST thuO'Ilg va long den tr.S :<br />

a. Mau long di truyn theo hin tuqng tinh tr(>i khong hoan toan.<br />

M : long den; Aa .: long xarih da troi;<br />

aa : long tning<br />

P : M (den) x aa (tnfog)<br />

b. Ket qua : 1 long den : 2 long xanh da troi : 1 long trang<br />

Cho biet & m(>t loai du, ht xam tr(,i hoan toan so vm ht tring.<br />

Du&i day la bang thong ke iY m{>t so phep lai :<br />

Kieu hinh cu.a p So cay' F 1<br />

mt xam<br />

Ht tring<br />

a. Ht xam x h;;tt tnfog 85 87<br />

b. ff;;tt xam x h;;tt xam 210 70<br />

c. Ht xam x ht trang 150 0<br />

Hay giiti thich va lp so· do cho m6i phep lai tren.<br />

f>.S : A : hc.1t xam, a : hc.1t triing<br />

a. P : Aa x aa; b. P : Aa x Aa; c. P : M x aa<br />

Bai 9 : Biet & trau, mau long den tr(>i hoan toan so voi mau long tr.ing<br />

va gen, qui dinh tinh trng m\m tren NST thuong.<br />

M(>t trau tr.ing (1) giao phoi voi m(>t trau den (2), de Ian thu nhat duoc<br />

m


F I<br />

: Kieu gen AaBb<br />

Kieu hinh 100% hc.1t vang trcm<br />

F 1<br />

: AaBb ( vang tran) x AaBb ( vang tron)<br />

GF 1<br />

: AB,Ab, aB, ab AB, Ab, aB, ab<br />

F 2 :<br />

Qd AB b aB<br />

---- --- -- ------<br />

AB MBB<br />

vang, tran<br />

AABb<br />

vang, tran<br />

AaBB<br />

vang, tron<br />

Ab<br />

aB<br />

ab<br />

MBb<br />

vang, tran<br />

AaBB<br />

vang, tron<br />

AaBb<br />

vang, tran<br />

AAbb<br />

vang, nhan<br />

AaBb<br />

.vang, tran<br />

Aabb<br />

vang, nhan<br />

AaBb<br />

vang, tron<br />

aaBB<br />

xarih, tran<br />

aaBb<br />

xanh, tron<br />

(J F 2<br />

c6 :<br />

Kieu gen<br />

Kieu hinh<br />

1 MBB<br />

2MBb 9A - B - 9 h9t vang, tron<br />

2 AaBB )<br />

4 AaBb<br />

1 Mbb<br />

2 Aabb } 3 A - bb 3 h


Biet hai cc}p tinh trq.ng chieu cao than va mau qua di truyen d


Bai 3: ()' mot loai xet hai tinh trng la hinh dng qua Va \'l qua . di<br />

. <br />

truyen d(>c lp VO'i nhau.<br />

- Ve d;,mg qu : qua trc>n tr(>i so VO'i qua dai va qua dt la tinh trng<br />

trung gian.<br />

- Ve VJ qua : qua ngQt tr(>i hoan loan so VO'i qua chua.<br />

a. Giao phan giua hai cay thuan chung mang cac gen tuong phan _<br />

vm<br />

"nhau, thu dUQ'C F I<br />

' roi cho cac cay F I<br />

iai phan tich Lp SO' do lai<br />

ctia P va ctia F 1<br />

•<br />

b. Cay bo co kieu hinh qua dai, chua lai vm cay m chua biet kieu g n<br />

thu dtrQ'C cac cay con deu co kieu hinh qua dt, ngQt. Xac djnh kieu<br />

gen ctia bo m Va lp SO' do lai.<br />

Theo de bai, ta c6 :<br />

GIAI<br />

Oc;ing qua di truyen theo hin tuqng tinh trqi khong hoan toan<br />

Qui UO'C A : qua trcm, a : qua dai<br />

M : qua tron, Aa : qua dt, aa : qua dai<br />

- Vi qua di trnyen theo hin tuqng tinh trqi hoan toan<br />

Qui u6c B : qua ngQt, b : qua chua<br />

a. So d6 lai ctia P vii ctia. F 1<br />

:<br />

Hai cay P thuan chung rqang cac gen tuong phan co the la :<br />

P : MBB x aabb hoc}c P : Mbb x aaBB<br />

* Sa d6 lai ciia P c6 hai tru&ng hqp :<br />

Truong hqp I P : MBB (qua tron, ngqt) x<br />

GP: AB<br />

F 1<br />

: AaBb<br />

I 00% qua dt, ngqt<br />

- Truong hqp 2 : P : Mbb (qua tron, chua) x<br />

GP: Ab<br />

F : 1<br />

AaBb<br />

I 00% qua dt, ngqt<br />

aabb (qua dai, chua)<br />

* Cho F 1<br />

lai phan tich :<br />

F deu la AaBb lai phan tich Ia lai v6i cay mang tinh lc}n: qua dai, chua (aabb)<br />

S do lai : F : 1<br />

AaBb (qua dt, ngqt) x aabb (qua dai, chua)<br />

GF 1<br />

:AB,Ab,aB, ab<br />

ab<br />

AaBb : Aabb : aaBb ·: aabb<br />

2 :<br />

Kieu hinh : I qua dt; ngqt : I qua dt, chua<br />

1 qua dai, ngqt : I qua dai, chua<br />

ab<br />

aaBB (qua dai, ngqt)<br />

aB<br />

b. Xtic djnh bo m va sa d6 lai :<br />

- 86 c6 qua dai chua : aabb tc;io m_y cay m tc;to m(>t loc;ii giao tu AB tuc mang kieu gen AABB (kieu hinh qua<br />

tron, ngQt).<br />

P : MBB (tron, ngQt) x bo aabb (dai, chua)<br />

GP: AB<br />

ab<br />

F 1<br />

: AaBb<br />

I 00% qua dt, ngqt<br />

Bai 4 : Tu m(>t phep lai giua 2 cay, nguoi ta thu dU't · cay di hqp Bb.<br />

P : Bb (h


* T6 hqp hai c


2. Tinh so lin nguyen phan, so te bao con to ra, so NST moi truong cung<br />

cap. cho te bao nguyen phan va so NST c6 trong cac te bao con<br />

a. Neu c6 m()l le bao. nguyen phan :<br />

Neu c6 te bao m (2n) tien hanh nguyen phan x Ian :<br />

* Tinh so' te bi1.0 con :<br />

Ta c6:<br />

- Te bao nguyen phan 1 Ian t90 2 = 2 I te bao con.<br />

- Te bao nguyen phan. 2 Ian to 4 = 2 2 te bao con.<br />

- Te bao nguyen phan 3 Ian lc;\O 8 = 2 3 te bao con.<br />

v.v ...<br />

Vy neu te bao nguyen phan x Ian thi so te bao con = 2 x .<br />

* So' NST c6 trong cck te' bao con :<br />

___ M6i le bao con du c6 chua b(> NST Iuong b(>i (2n) giong te bao m.<br />

Vf).y so NST trong cac le bao con duqc t9o ra = 2 x • 2n<br />

* So NST moi truong cung c;ap cho te bao nguyen phan :<br />

BAng so NST trong cac te bao con. duqc t9o ra tru so NST 2n clia 1 te bao<br />

m ban dau:<br />

2 x . 2n - 2n = (2 x - 1) . 2n<br />

b. Neu c6 nhi€u te bao nguyen phan v6i so Mn bdng nhau :<br />

. Neu c6 a le bao m (2n) deu lien hanh nguyen phan x Ian being nhau.<br />

Bin luf).h tuang lll nhu tren, ta c6 :<br />

L.J;.; 266<br />

Suy ra b(> NST 2n : 2n = --- = -·-- = 38<br />

.<br />

2 x - 1 2 3 - I<br />

- Vf).y 2n = 38<br />

b. - So' le bao con dU(JC [(JO ra: 2 x = 2 3 = 8 (le bao)<br />

- So' NST lrong ccic te' bao con : 2 x . 2n = 8 . 38 = 304 (NST)<br />

> Thi di!- 2<br />

C nam le bao ·cua chu(>t (2n = 40) deu tht1c hin nguyen phan 1 Ian.<br />

Xac dinh:<br />

a. So NST cung lrc;lng thai NST va so cromatit trong cac te bao O ki ghia.<br />

b. So NST cung trc;ing thai va so cromatit trong cac te bao a ki sau.<br />

c. So le bao con sau nguyen phan a so NST trong cac te bao con.<br />

a. a ki giua :<br />

HUONG DAN .GIAI<br />

r-. - So NST cling trc;ing thai trong cac te bao :<br />

2n kip x 5 = 40 NST kep x 5 = 200 (NST kep)<br />

- So cromatit trong cac te bao :<br />

4n x 5 =. 2 x 40 x 5 = 400 (cromatit)<br />

b.•O ki sau:<br />

- So NST cung trc;ing thai trong cac te bao :<br />

4n don x 5 = 40 x 2 x 5 = 400 (NST don)<br />

- So cromatit trong cac te bao = O<br />

, c. - So te bao con sau nguyen phan : a. 2x = 5 x 2 1 = 10<br />

* Tong so' te' bao con sau nguyen phan = a . 2x<br />

,<br />

, , A' , .<br />

*<br />

x<br />

So A NST co lrong cac te bao con = a . 2 • 2n r · . . .. . • · · • · -<br />

·<br />

i> Thi du 3<br />

* So' NST m6i lruang wng cap cho a le bao lien hilnh qua trinh nguyen I > ,, .A<br />

phan == (2 x - 1) • a . 2n<br />

, , , , ;: . .<br />

112 THI DI) VA HUO'NG DAN GIAI<br />

> 7:'i di!- I<br />

C6 m(>t hqp tu cua loai nguyen phan 3 Ian va da nhn ctia moi truong nguyenl<br />

liu tuapg duong v6i 266 NST.<br />

. · Xac djnh :<br />

a. Be') NST 2n.<br />

r· ".""" So NST trong cac te bao ·. 10 2n = 10 40 - 400 (NST)<br />

I· Co mqt S A ? t bao smh duang cua tho deu nguyen phan 5 Jin lien t.iep, va da<br />

,.., A, , •<br />

_ •<br />

. l ij.<br />

O ra 320 te bao con. Cac le bao con tc;io ra c6 chua 14080 tam dOng.<br />

t . Xac dinh: a. So te bao sinh du6ng ban dau.<br />

f _<br />

. . -<br />

b. So NST moi truong da cung cap cho cac te bao nguyen phan.<br />

fqJS6 td bao sinh di.rang ban ddu<br />

HU'ONG DAN GIAI<br />

f /G9i a la so te bao sinh duong ban dau.<br />

Suy ra so te bao con sau nguyen phan :<br />

b. So t bao con duqc to ra va so NST c6 trong cac. te bao con.<br />

Ft . a · 2 x = 320 =><br />

a. 89 NST 2n:<br />

So NST moi truong cung cap : · (2 x - 1) . 2n = 266<br />

64<br />

HUONG DAN GIAI ib,, S o NST moi trurmg cung ca p :<br />

! ,) ) So NST bang so tam d<br />

a = 3 0<br />

: 3 x = : 5 ° = IO (te Jtao) ·<br />

2n = 14080 = 44<br />

. 320<br />

65<br />

I


So NST moi truang cung cap cho nguyen phan<br />

(2 x - 1) . a . 2n = (2 1 - 1) . 4 . 78 = 312 (NST)<br />

b. S6 NST cung trqng thai, s6 cromatit trong ccic te bao :<br />

Theo de bai trong Ian nguyen phan da neu<br />

Ki trung gian = 4 phut<br />

.,- - Ki dau = 3 phut<br />

Ki giua = 3 phut<br />

- Ki sau = 3 phut<br />

- Ki cuoi = 3 phut<br />

* Sau khi eek te bao nguyen phan duqc 2 phut :<br />

Cac te bao dang 6 ki trung 'gian, va trong cac te bao c6 :<br />

- So NST cung tr9ng thai : 2n kep x 4 = 78 x 4 = 312 (NST kep)<br />

- So cromatit : 4n x ·4 = 78 x 2 x 4 = 624 (cromatit)<br />

* Sau khi ccic te bao nguyen phan dU NST cua loai nguai.<br />

* S6 NST c6 trong loan b() cac te bao con :<br />

28 x 2n = 28 x 46 = 1288 NST<br />

. . .<br />

B i 5 _ : 6 m\m te bao cua lit nha nguyen phAn mc}t so Ian bing nhau<br />

va da su d m6i truong 2800 NST. Cac t bao con tao ra c6<br />

chua tat ca 1 _<br />

200 NST<br />

Xac djnh : "-· ... ___ /<br />

a. So NST lu6ng b(,i cua Vit nha.<br />

b. n nguyi!n phAn <br />

tia _<br />

m6i ti bBo.<br />

c. So tam d(,ng trong cac te bao con duc,c t,o ra.<br />

a. S6 NST luung b()i cua v;t nh.a :<br />

GIAI<br />

_,<br />

. . .<br />

(<br />

__<br />

$· ) . • ,< n .::c- £ J. oD .<br />

. (1,) 1)<br />

So NST trong narn le bao m (bang so NST trong cac te bao con tru so NST<br />

moi truong cung cap) :<br />

.<br />

So· NST t ,, . ,., b'<br />

3200 - 2800 = 400 (NST)<br />

400<br />

· rong ffiOl te ao : 2n = - = 80<br />

b. S6 l&n nguyen phtin clia 11Wi t b:o :<br />

Gqi x la s6 Ian nguyen phan cu; moi te• bao.'<br />

Suy ra so NST trong cac te bao con :<br />

a · 2 x . 2n = 3200 . 5 . 2 x . 80 = 3200<br />

Vy x = 3.<br />

.<br />

JP;<br />

5 l;l x Q :;:: tt1 .<br />

\. . l ,' (\<br />

'· f_)) <br />

.)<br />

J q O t S<br />

.. ·- -.· .·<br />

1 ') £ {. -<br />

· t i\ t0<br />

r;,L, ()\ ,,<br />

..:·/ "' . 'if 1 .._ ..•<br />

=} 2 x = 3200 = 8?;,/ 2 3 ,<br />

400<br />

c. S6 tam d(mg trong cac le bao co,:, bdng s6 NST trong cac te bao con· bang<br />

3200 (tam dc)ng).<br />

68<br />

69


{Jh(i<br />

- Ki trung gian I :<br />

Cac NST nhan doi t9o cac NST kep. Moi NST kep g6m c6 hai cromatit giong<br />

Mt nhau, dinh nhau a tam dQng. .<br />

- Ki ddu I:<br />

Cac NST kep co xocin va ngcin dan 19i, c6 d9ng dc}c trung va xep thanh hai<br />

hang tren mc}t phang xich d90 cua thoi VO si1c.<br />

- Ki sau I:<br />

Moi NST kep trong tung cc}p tuang d6ng phan Ii ve mqt ClJC cua le bao.<br />

- Ki cuoi I:<br />

BQ NST kep don bQi (n) trong te bao con t90 ra van co xoAn.<br />

* (J ldn phan bao II :<br />

- Ki trung gian II va ki ddu II :<br />

Cac NST khong nhan doi va giu nguyen tr9ng thai co xoAn nhu a ki cuoi I.<br />

-'- Ki giua II:<br />

Cac NST kep xep mQt hang tren mt phfing xich dc;10 cua thoi vo sic.<br />

Moi NST kep tach tam dQng to thanh hai NST don phan Ii deu v hai ClJC<br />

:<br />

C, , . ,.,b,<br />

1<br />

\ { nv r / \<br />

a. ac oq1 le ao con dUQ'c tqo ra sau gwr;:( pht tho cai giam phan. Xac djnh so te bao hung<br />

NST la co che dan den hinh thanh bQ NST don bQi (n) trong cac giao tu. i. v a so th e d 1nh huang duqc l90 ra cung so NST chua trong tat ca trung voi the '<br />

· · · bA NST d bA' ,<br />

- Trong thlJ tinh, SlJ to hqp g1ua ha1 Q . an QI tu giao tu \JC va giao !<br />

tu cai cung Ioai giup tcJ.o ra bQ NST luong bqi trong hqp tu.<br />

Nhu vy SlJ ket hqp gilia giam phan va lhl) tinh la CO' che cua SlJ on dinh<br />

bQ NST 2n dc}c trung ctia loai qua cac the M CO' the khac nhau.<br />

Thong qua hai qua trinh giam phan va thtJ tinh, a sinh vt da tc)o ra nhieu t6 :<br />

hqp NST khac nhau a d&i con, lam xuat hi¢n nhiu bien di to hqp, tang tinh<br />

phong phu, da dcJ.ng a sinh vt, c6 y nghia doi voi lien h6a va chQn giong.<br />

. • •<br />

11. CAc DANG BAI TAP VE GIAM PHAN VA THU TINN<br />

11 • MOT s6 CONG THU'C AP DUNG<br />

.<br />

. d<br />

, . djnh huong. Biel a tho 2n = 44<br />

HU'O'NG DAN GIAI<br />

So trung duqc l90 ra = So noan baa bi[Lc I = 5 (trung)<br />

So the dinh huong = 3 Ian so noan bao bc I :<br />

3 x 5 = 15 (the d!nh huong)<br />

S6 NST trong cac trung vii the djnh htrong :<br />

> Thi di! 2<br />

(5 + 15) . n = 20x 44 = 440 (NST)<br />

2<br />

/\<br />

Ji<br />

( !:( I L/ '<br />

- 4 <br />

(<br />

::.--- ) ·<br />

Lie<br />

JS JL<br />

'tj }'l ·-:;;.. (l,,-<br />

L1 i<br />

11 --::=- · ) .,:..---<br />

, co mQ'. 56 tinh bao bi).c I cling loili qua gi.im pMn da t90 ra IH tinh trllng. tt.J/.j<br />

1. Cong th t inh so te bao con va so NST trong cac te bao con d m, c t f o .<br />

Xac djnh : a. So tinh bao bac I.<br />

1 • •<br />

,<br />

n (<br />

1 , ,'· 1 (!('(1) t/\_ fS ·<br />

.<br />

1,;v<br />

b. Ten ctia Ioai. r lJ l<br />

-<br />

JVl ,., 1<br />

,;?l<br />

72 73<br />

ra sau g1am phan<br />

So NST co trong cac tinh trung bang 3312


.. . .<br />

a. S6 thl djnh hmmg dugc t()o ra :<br />

GIAI<br />

S6 te bao con sau nguyen. phan = S6 noan bao bc I :<br />

a . 2 x = 3 . 2 5 = 96<br />

S6 the dfnh huang duqc li;l.O ra sau giam phan :<br />

b. S6 hw tu duvc t n = = 19<br />

ra 2n = 38.<br />

48<br />

76<br />

77


Cbuong Ill:<br />

I. MOT SO KIEN THlfC CO' BAN<br />

I. AON, gen va St;f ll! nhan doi<br />

ADN, GEN VA ARN<br />

a. Cdu l- so:, luon g va trinh ttJ khac nhau t9o cho AON vua co tmh da dq.n g , vua<br />

l<br />

p an .<br />

co tinh dc thu.<br />

* Cau true khong gian cua ADN :<br />

__ AON co hai mq.ch song son g va xoan quanh mt tnJc teo hieu ti uaJ<br />

hai tq.o thanh cac vong xoc1n man g tinh chu ki (c_ k1 ?a). M1 v?ngl<br />

I,> , h , 20 nucleotit xep thanh 1 O cap nu; ch1eu da1 cua mQt vong<br />

l<br />

b. Qua trinh tong hqp ARN<br />

xoan co c ua<br />

xoan<br />

. , · , . o<br />

bcln g 34 A 0 (do m6i nudeotit c6 ch1eu dal 3,4 A ).<br />

A<br />

A<br />

•<br />

h<br />

A<br />

- Truyen thong tin di truyen qua cac the h nho co kha nang llJ nhan doi.<br />

d. Qua trinh tv nhan doi cua ADN<br />

Qua trinh ttJ nhan doi (con gQi la ttJ sao, sao chep, tai ban) ctia AON dien<br />

ra theo CO che sau day<br />

Dau tien, enzim tac dt_mg lam thao xoan va tach roi lien ket giua hai ffiq.Ch<br />

don.<br />

Cac nucleotit ctia moi truong sau do Ian luqt vao lien ket vai cac nucleotit<br />

tren hai mq.ch ctia AON theo dung nguyen tci.c b6 sung (A-T, G-X).<br />

Ket qua tu I AON nhan doi 1 Ian lq.o 2 AON con giong ht nhau va giong<br />

phan tu AON m.<br />

f a. Cdu l


.<br />

l<br />

; ··<br />

-.<br />

..<br />

.<br />

._<br />

--<br />

.<br />

·<br />

.<br />

.<br />

HUONG DAN GIAI<br />

- So luqng nucleotit cua gen bAng 2 Ian s6 Juqng ribonucleotit cua phan tu<br />

mARN:<br />

N = 2 x 1200 = 2400 (nu.)<br />

,<br />

N o<br />

2400<br />

Ao 4080 (A o )<br />

Trt hJ cac c"«}p nucleotit cua ca do9n gen la :<br />

T - G X- A A- G -<br />

I I I I I I<br />

A '- - X- G- T - T - X-<br />

.<br />

i,. Trq.1111 ctic c(ip nucleolit tren hai do(Jn gen con :<br />

T- X- A -...<br />

I I I<br />

A- G- T.-... ·<br />

- Chieu dai cua gen: L =<br />

2 x 3,4/\ = - 2 -x 3,4 = Do9n gen nhan doi 1 Ian tqO hai do9n gen con giong hf;t nhau Va giong do9n<br />

- So luqrig nuclMtit' c6 trong cac gen· con t90 ra sau 3 Ian nhan doi :<br />

2 x . N = 2 3 . 2400 = 19200 (nu.)<br />

> Thi dl,l 3<br />

C6 nam gen co cau true gi6ng nhau du nhan doi voi so Ian bAng nhau, cac gen<br />

con t;;to ra c6 chua tong so 60000 nucleolit. Biel m6i gen c6 chiu dai.5100 A 0 :<br />

Mc djnh:<br />

a. So Ian ttJ nha doi cua m6i gen.<br />

b. So Iuqng nuclef>tit moi truong cung cap cho cac gen nhan doi.<br />

. a S6 ldn II! nhan doi cua m6i gen :<br />

.<br />

"<br />

HUONG DAN GIAI<br />

2 L . 2 x 5100<br />

So luqng nuclMtit cua moi gen :N =<br />

M = 3,4<br />

· = 3000 (nu.)<br />

GQi. x I.a so Ian ttJ nhan doi cua m6i gen. Theo d bai, suy ra so nucleotit c6<br />

trong cac gen con<br />

a . 2 x . N = 60000<br />

. 2 x = 60000 . N 60000 . 3000 = 4<br />

Suy ra<br />

a 5 ·-<br />

2 x = 4 = 2 2 => X = 2<br />

Vy Iiloi gen ttJ nhan doi 2 Ian.<br />

b. Stf luc;mg nudeotit moi In.rang cung ctfp cho eek gen nhan doi :<br />

> Thi dl,l 4<br />

(2 x -1) . a . N = (2 2 - 1) · 5 · 3000 = 45000 (nu.)<br />

Cho 1 m9ch tren mi m t s6 lin bing nhau va C,a su dt;mg cu.a ml>i truang 33600<br />

nucleOtit<br />

· Xac djnh:<br />

a. Tong s6 gen con da. duqc t,o ra sau qua trinh nhin dl>i n6i tren va<br />

.<br />

s6 lin nha\n d6i c!ia m6i gen.<br />

b. Chiu dai cua m6i gen.<br />

·· c. S6 _ luqng nuclMtit c6 trong m6i phan tu mARN do m6i · gen noi tren<br />

..<br />

I•<br />

,.. t6ng hqp.<br />

,, ..<br />

GIAI<br />

r.S6 gen con vil s6 i&n nhan d6i ct.ia m6i gen:<br />

[? So Iuqng nucleotit-cua m6i gen : N = C x 20 = 60 x 20 = 1200 (nu.)<br />

i :<br />

··.·<br />

;<br />

.·<br />

._ . ···. , ··<br />

··<br />

_-.-<br />

. GQi x la so Ian n han 1 d6i cua m6i gen; Suy ra so luqng nuclMtit moi truong<br />

. _ ci:ung cap cho cac gen nhan doi :<br />

(2<br />

L"· x -I) . a . N = 33600<br />

T .:c G -·X-A-A-G-T-X-A-...<br />

. t, _ i _ __ '-__ ··.-.·-_- ·. •_-._- . . _ _<br />

. i, · ·· 8 uy ra : = -- + = - -<br />

.<br />

2 x . 33 _ _ _ 6 00<br />

I<br />

. 33600 . I 8<br />

a. Viet trt hJ cac nucleotit a mch con lc;ti cua do9n gen va cua ca do9n gen}\ a . N 4 x 1200<br />

b. u do9n gen tren ttJ nhan doi 1 Icin. Hay viet trt ttJ cac cp nucleotit tren Ne·<br />

·. 1 <br />

·.·· : ·•·<br />

.. .<br />

cac do9n gen con.<br />

HUONG DAN GIAI<br />

h , . 1 .<br />

a. Tr(it II! ctic nucleotit a ffl


.<br />

x N<br />

S6 ribonucleotit c6 trong cac phan tti ARN : 2 x 2 = 24000<br />

x 24000 4<br />

Suy ra 2 = = 16 = 2 ==> x = 4<br />

1500<br />

V{J.y gen da nhan doi 4 Ian.<br />

So luqng nucleotil c6 trong cac gen con<br />

2 x . N = 16 x 3000 = 48000 (nu.)<br />

So luqng nucleotit moi truong cung cap cha gen nhan d6i<br />

· (2 x .. 1) . N = (16 - I) . 3000 = 45000 (nu.)<br />

..... -------------·<br />

lh'lli 5 : Co m(H mteh tren dm,m gen co trt ll! irac nucleom nhu sau :<br />

A-X-'f-G .. A-T-A-X-G-G-T-A- •••<br />

a. Hay viet trt tit;f CZlC rmcleotit cina mch con ii va ca dom gen.<br />

b. Ne'u don gen nay i\? :nhan doli 3 Ian. Hay xac dtnh :<br />

* So luqng nudeotit moi trui>'ng ct.mg cap.<br />

* So .nudeom co in·ong care gen cm11.<br />

* Viet. t1 r t hl cii.::c p i!H.lldeoW: tir:ong ,n1oi «l!OM)ln gen con.<br />

_....,.,.._ ..._ _,,....,.. ,....,. ... ,..__,.._----=-'r-=--• --""""----,-.,,,.,._,l,_c,._..,...,.,.,,.._,...,.,,_,...,___._.., ...... __....,..., .,.. , _ • •<br />

GIA;<br />

Go Tr(it Ii! clux ffl(iCh com. ff{jii 'i}(jj ([;J:J{}j ca tilO(Jill?i ,gen :<br />

Theo nguyen tac b6 sung A mch nay lien ket val T H1q.Cl1 Ida va G rn,;i.ch n;:'iy<br />

lien ket voi X mch kia, nen tr?,tt h.,r cac nuchom cl'.ia m0ch c6n ld !,\<br />

T-G-A-}( .. T .. A--T-G-X··X .. ft.··T- .. .<br />

Va trt llJ cac cp nud:Mtit Cl!a ca do(;°U.1 gen lit<br />

A- x T - G .. A .. T .. J\ -<br />

I I I I I I I<br />

T G A·· x · 'f. A .. T ..<br />

b. Neu dogn gen hl TRharn d6J 3 idro ;·<br />

Don gen c6 12 ci}p nucie()tit = 24 nucleotit<br />

* So' lm;mg nucle6tif m6i tmong cung cap<br />

(2 x - l) . N -= (2 3 - 1) . 24 =:. 168 {nu.)<br />

* So' nucle6tit c6 trong cac gen con :<br />

2 x . N ::c: 2 3 . 24 :.::: i 9:2. ( nu.)<br />

x ..<br />

!<br />

G<br />

* Trgt f l! cac cijp nucleotif co trong m6i doqn gen con :<br />

Moi do


PHAN II<br />

Chuong I<br />

ff NII 11@1 llil MDI TllUON,<br />

I. MOT SO Kl(N THli'C CO' BAN<br />

<strong>SINH</strong> V!T VA MOI TRUO'NG<br />

1. Moi truong va nhan t6 sinh thai<br />

a. Moi truqng<br />

Moi truong la noi sinh song cua sinh vt, bao g6m tat ca nhung ? i bao<br />

quanh chung. , A.<br />

C6 bon lo9i moi truong chu yeu· : moi truong dat, moi truong nuoc, mm<br />

truong tren mt dat - khong khi va moi truong nuoc.<br />

b. Nhtin 16 sinh lhai<br />

vat.<br />

Nhan to sinh thai la tat ca nhung yeu to cua moi truong tac d(mg den sinh<br />

. C6 hai nh6m nhan to sinh thai la nh6m nhan to VO sinh va nh6m nhan to<br />

huu sinh.<br />

_ Nham nhan t6 VO sinh : bao g6m nuoc, nhit d(>, anh sang, gi6, bao ...<br />

_ Nham nhan 16 hiru sa11h : bao g6m con nguoi va cac d,;mg sinh vt khac.<br />

2. Anh huong cua cac nhan t6 sinh thai leil sinh vl)t<br />

a. Tac d()ng cua .cac nhtin 16 VO sinh<br />

* Tac d()ng cua nhng cua anh sang len sinh vc}t :<br />

Tuy theo kha nang thich nghi cua sinh vt voi nhan to anh sang, nguoi<br />

phan chia hai nhom sinh vc}t 1a nhom sinhvt ua san8 :<br />

va·nhom sinh vt ua to1.<br />

_:__ Tac dong cua nhit d(> :<br />

Tuy theo muc d(> aph huong cua nhit d(> doi voi co the, nguoi ta phan<br />

chia hai nh6m sinh vt<br />

• Nh6m sinh vt bien nhit bao g6m vi sinh v


GIAI<br />

a. Sa d6 tac d


Cac con ho duqc nuoi trong vuan bach thu.<br />

Cac con cho nuoi.<br />

- Cac con cho soi trong rung.<br />

- Cac cay rung trong mqt khu rung.<br />

Hay cho biet tp hqp nao la quan the, tp hqp nao khong phai quan the va<br />

tp hqp nao la quan xa sinh vt?<br />

HUONG DAN GIAI<br />

a. Nhung ttjp hqp la qudn the sinh vtjt :<br />

- Cac ca the loai tom song trong hf>.<br />

- Cac con tho trong mqt khu rung.<br />

- ·Cac con ch6 soi trong rung.<br />

b. Nhiing ti;p hqp khong phcii qudn the sinh VQt :<br />

- Cac con ho duqc nuoi trong vuan bach thu.<br />

- Cac con ch6 nuoi.<br />

c. Nhiing ttjp hqp la qudn xii sinh vtjt :<br />

- Cac ca the ca trong ao.<br />

- Cac con chim song trong rung.<br />

- Cac cay rung trong mqt khu rung.<br />

Thi du 2<br />

Cho ac loai sinh vt sau : cay xanh, tho, ho, meo, chuqt, vi sinh vt, chim<br />

d9i bang.<br />

Hay neu 5 chuoi thuc an co the co tu cac loai neu tren.<br />

HUONG DAN GIAI<br />

- Cay xanh -tho -ho -vi sinh vt.<br />

- Cay xanh ..:..... tho -d9i bang -vi sinh vt.<br />

Cay xanh -chuqt -meo -vi sinh vt.<br />

- Cay xanh -chuqt -di bang -vi sinh vt.<br />

- Cay xanh -chuqt __,.. meo -ho -vi sinh vt.<br />

(Ghi chi, : hQC sinh CO the l!J lit ke chuoi thuc an khac tu cac loai tren).<br />

Ill. BAI TAP MAU<br />

· Bai 1 : Cho I luoi thuc an sau day :<br />

Rain -d,i bang<br />

Chu(>t/.l /<br />

Cay xanh / " Meo . Vi sinh vtt<br />

" Sau an la -Chim an stu/<br />

Hay lit ke tat ca cac chu6i thuc a ctia Iu6i thuc an tren.<br />

Cac chuoi thuc an<br />

GIAI<br />

- Cay xanh -chuqt -ran -di bang --vi sinh vt.<br />

- Cay xanh --chuqt -meo -ran --d9i bang --vi sinh vt.<br />

- Cay xanh --chuqt -meo --d9i bang --vi sinh vt.<br />

- Cay xanh --chuc)t -meo -vi sinh vt.<br />

- Cay xanh --sau an la -chim an sau --vi sinh vt.<br />

Bili 2 : Cho m(>t. so d6 lu6i thuc an sau :<br />

3<br />

/ <br />

(2<br />

<br />

(6)<br />

7<br />

5)<br />

(I)<br />

Biet cac loai ctia lu6i thuc an tren la : cao, cAy xanh, soi, tho, vi khuin<br />

phAn giai va ho.<br />

Hay xac dJnh ten sinh vt cho moi mat xich trong lu6i thuc an.<br />

(I) : cay xanh (2) : tho<br />

( 4) : ho<br />

GIAI<br />

(3) : Soi<br />

(5) : Vi khuan (6) : cao<br />

Bai 3 : Cho m(>t SO' d6 hr6i'thuc an sau day :<br />

Cay xanh<br />

Sau<br />

ThO<<br />

Chim an sau<br />

. >Vikhmfo<br />

./S6i<br />

De<br />

Chi<br />

gll'O'i<br />

/<br />

Ngoai cay xanh va vi khuan, trong cac mat xich con l

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