VbvNeuE-001

28 CHAPTER 4. DISCUSSION
neutron and its decay energy. In this case, all relativistic effects described by
( ) −1/2
the terms with coefficients 1 − v2
c compensate each other and completely
2
fall out. The neutron considered in our model is the quantum object. Its radius
R 0 is proportional to the Planck constant . But it can not be considered as
( ) −1/2
relativistic particle, because coefficient 1 − v2
c is not included in the definition
of R 0 . In the particular case of the calculation of the magnetic moment
2
of the neutron and the energy of its decay, it allows to find an equilibrium of
the system from the balance of forces, as it can be made in the case of nonrelativistic
objects. The another situation arises on the way of an evaluation of
the neutron lifetime. A correct estimation of this time even in order of its value
do not obtained at that.
For the above proton model (Fig.2.1), there is no question about what are
quarks in a free state.
However, it remains unclear what interactions joins these quarks together in
completely stable particle - proton, which decays in nature is not observed. It
is not clear why positron-quark and electron-quark are not annihilate.
But antiproton with the same structure is unstable.