VbvNeuE-001
Boris V. Vasiliev About Quantum-Mechanical Nature of Nuclear Forces and Electromagnetic Nature of Neutrinos
Boris V. Vasiliev
About Quantum-Mechanical Nature of Nuclear Forces
and Electromagnetic Nature of Neutrinos
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11.3. MESONS AS EXCITED STATES OF ELECTRON 55<br />
and we get<br />
S = n<br />
(<br />
1 −<br />
)<br />
α<br />
2 √ . (11.11)<br />
1 − β 2<br />
Where α = e2<br />
c<br />
is the fine structure constant.<br />
1<br />
According to Eq.(11.11) at the condition S = 0, the relativistic factor<br />
is equal to 2/α. Wherein, the mass of the particle is<br />
√<br />
1−β 2<br />
M 0 = 2 α m e = 274.08 m e . (11.12)<br />
This value of mass is very close to the mass of π-meson (11.7), which has a spin<br />
equal to zero:<br />
M 0<br />
M π ±<br />
1<br />
At spin S = /2, the relativistic coefficient √<br />
1−β 2<br />
≃ 1.003 (11.13)<br />
equal to 3/2α (at n=2)<br />
and mass of particle<br />
M 1/2 = 3<br />
2α m e = 205.56 m e . (11.14)<br />
This value of mass is very close to the mass of µ meson (11.7) which has spin<br />
= /2:<br />
M 1/2<br />
M µ ±<br />
≃ 0.9941 (11.15)
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