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Mathematical Reasoning- Writing and Proof, Version 2.1, 2014a

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156 Chapter 3. Constructing <strong>and</strong> <strong>Writing</strong> <strong>Proof</strong>s in Mathematics<br />

21. (a) Determine several pairs of integers a <strong>and</strong> b such that a b .mod 5/.<br />

For each such pair, calculate 4a C b, 3a C 2b,<strong>and</strong>7a C 3b. Are each<br />

of the resulting integers congruent to 0 modulo 5?<br />

(b) Prove or disprove the following proposition:<br />

Let m <strong>and</strong> n be integers such that .m C n/ 0 .mod 5/ <strong>and</strong> let<br />

a; b 2 Z. Ifa b.mod 5/, then.ma C nb/ 0.mod 5/.<br />

22. Evaluation of proofs<br />

See the instructions for Exercise (19) onpage100 from Section 3.1.<br />

(a) Proposition. For all integers a <strong>and</strong> b, if.a C 2b/ 0.mod 3/, then<br />

.2a C b/ 0.mod 3/.<br />

<strong>Proof</strong>. We assume a; b 2 Z <strong>and</strong> .a C 2b/ 0.mod 3/. This means<br />

that 3 divides a C 2b <strong>and</strong>, hence, there exists an integer m such that<br />

a C 2b D 3m. Hence, a D 3m 2b. For.2a C b/ 0.mod 3/,there<br />

exists an integer x such that 2a C b D 3x. Hence,<br />

2.3m 2b/ C b D 3x<br />

6m 3b D 3x<br />

3.2m b/ D 3x<br />

2m b D x:<br />

Since .2m b/ is an integer, this proves that 3 divides .2a C b/ <strong>and</strong><br />

hence, .2a C b/ 0.mod 3/.<br />

<br />

(b) Proposition. For each integer m, 5 divides m 5 m .<br />

<strong>Proof</strong>. Let m 2 Z. We will prove that 5 divides m 5 m by proving<br />

that m 5 m 0.mod 5/. We will use cases.<br />

For the first case, if m 0.mod 5/,thenm 5 0.mod 5/ <strong>and</strong>, hence,<br />

m 5 m 0.mod 5/.<br />

For the second case, if m 1 .mod 5/, thenm 5 1 .mod 5/ <strong>and</strong>,<br />

hence, m 5 m .1 1/ .mod 5/, which means that m 5 m <br />

0.mod 5/.<br />

For the third case, if m 2 .mod 5/, thenm 5 32 .mod 5/ <strong>and</strong>,<br />

hence, m 5 m .32 2/ .mod 5/, which means that m 5 m <br />

0.mod 5/.

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