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Mathematical Reasoning- Writing and Proof, Version 2.1, 2014a

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184 Chapter 4. <strong>Mathematical</strong> Induction<br />

(b) Why is it not possible to use mathematical induction to prove a proposition<br />

of the form<br />

For each real number x with x 1, P.x/,<br />

where P.x/ is some predicate?<br />

18. Evaluation of proofs<br />

See the instructions for Exercise (19) onpage100 from Section 3.1.<br />

n.3n 1/<br />

(a) For each natural number n, 1 C 4 C 7 CC.3n 2/ D .<br />

2<br />

<strong>Proof</strong>. We will prove this proposition using mathematical induction.<br />

So we let P.n/ be the open sentence<br />

1 C 4 C 7 CC.3n 2/:<br />

Using n D 1, we see that 3n 2 D 1 <strong>and</strong> hence, P.1/is true.<br />

We now assume that P.k/ is true. That is,<br />

k.3k 1/<br />

1 C 4 C 7 CC.3k 2/ D :<br />

2<br />

We then see that<br />

.k C 1/ .3k C 2/<br />

1 C 4 C 7 CC.3k 2/ C .3.k C 1/ 2/ D<br />

2<br />

k.3k 1/<br />

.k C 1/ .3k C 2/<br />

C .3k C 1/ D<br />

2<br />

2<br />

3k 2 k C .6k C 2/<br />

D 3k2 C 5k C 2<br />

2<br />

2<br />

3k 2 C 5k C 2<br />

2<br />

D 3k2 C 5k C 2<br />

:<br />

2<br />

We have thus proved that P.k C 1/ is true, <strong>and</strong> hence, we have proved<br />

the proposition.<br />

<br />

n.3n 1/<br />

(b) For each natural number n, 1 C 4 C 7 CC.3n 2/ D .<br />

2<br />

<strong>Proof</strong>. We will prove this proposition using mathematical induction.<br />

So we let<br />

P.n/ D 1 C 4 C 7 CC.3n 2/:

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