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i29 formulas

Formula

q

3-1

= A

k ⎞

⎜can ∆ x ⎠

⎟ (∆T therefore ) be

modified into Formula 3-2:

Formula 3-2:

q = A R (∆T )

Where:

q = rate of heat transfer through the

material (Btu/hr)

R = ∆ x

R = thermal i29 resistance formulas

k (or “R-value”)

of a material (ºF•hr•ft 2 /Btu)

∆T = temperature difference across

the material (°F) ⎛

A = area heat q q = flows AhA(∆T k ⎞

across (ft 2 )

∆ x ⎠

⎟ ) (∆T )

The R-value of a material can be

determined based on its thermal

conductivity (k), and its thickness

(∆X). The relationship q = is given as

Formula 3-3. q = sAF A T 4 4

− T

R (∆T 12 ( )

1 2 )

⎡ 1

+ 1 ⎤

⎢ −1⎥

Formula 3-3: ⎣ e 1

e 2 ⎦

R = ∆ x

k

Where:

Re# = vdD

k = thermal conductivity µ of the

material (Btu/°F•hr•ft)

q = hA(∆T )

∆x = thickness of the material in the

direction of heat flow (ft) ⎛ 1 ft ⎞

d = (0.811 in)

The U-values and R-values

12 in⎠

of

materials used to build heat

exchangers q are = sAF critically T 4 4

12 ( − T

1 important.

2 )

In general, materials ⎡ 1and thicknesses

that provide high ⎛ U-value, and thus

low R-value, v allow = 0.408 + 1 ⎤

⎢ ⎞

−1

⎜ for higher thermal

d 2 ⎠

⎟ f

⎣ e 1

e 2 ⎦

performance when heat needs

to pass through a solid material

separating the two fluids.

Re# = vdD

CONVECTION

v = 0.408 µ ⎞

Convection heat ⎝

transfer d 2 ⎠

⎟ f occurs = 0.408

⎜ 0.811 as

the result of fluid movement. The fluid

⎛ 1 ft ⎞

can be a liquid d or = a (0.811 gas. in)

12 in⎠

When heated, fluids expand. This

lowers their density relative to

surrounding cooler fluid. Lowered

density increases ⎛ buoyancy, which

causes the v warmer = 0.408 ⎞

fluid to rise.

Examples of the

latter

d 2

include

⎟ f

warm

air rising toward the ceiling in a room

and heated water rising to the upper

portion of tank-type water heater.

Both processes occur without

circulators or blowers. As such, they

are examples of “natural” convection.

Convection heat transfer is also

responsible for moving heat between

a fluid and a solid.

For example, consider water at

100ºF flowing along a solid surface

that has a temperature of 120ºF. The

cooler water molecules contacting

the warmer surface absorb heat from

that surface. These molecules are

churned about as the water moves

along. Molecules that have absorbed

heat from the surface are constantly

being swept away from that surface

into the bulk of the water stream and

replaced by cooler molecules. One

can envision this form of convective

heat transfer as heat being “scrubbed

off” the surface by the flowing water.

The speed of the fluid moving over

the surface greatly affects the rate of

convective heat transfer.

Most people have experienced “wind

= 0.06758 chill” ftas cold outside air blows past

( ) 2

Figure 3-2

5 = 3.1

ft

sec

= 0.06758 ft

them. They feel “colder” compared

to how they would feel if standing

in still air at the same temperature.

The faster the air blows past them,

the greater the rate of convective

heat transfer between their skin or

clothing surfaces and the air stream.

Although the person may feel as if the

moving air is colder, it isn’t. Instead,

they’re experiencing an increased

rate of heat loss due to enhanced

convective heat transfer. Achieving

the same cooling sensation from

calm air would require a much lower

air temperature.

Convective heat transfer increases

with increasing fluid speed. This

happens because a layer of fluid

called the “boundary layer,” which

clings to surfaces, gets thinner as

the fluid’s velocity increases (see

Figure 3-2).

The thinner the boundary layer,

the lower the thermal resistance

between the core of the fluid stream

and the surface. Less thermal

resistance allows for higher rates

of heat transfer between the fluid

molecules in the core of the stream

and the tubing wall.

tube wall

boundary layer of slow moving fluid limits convection

velocity profile of fluid

Note low velocity near tube wall.

"core" of flow stream

heat flows from water,

through boundary layer, tube

wall, into surrounding material

28

v = 0.408 ⎞

d 2 ⎠

⎟ f = 0.408

ft

⎜ ⎟ 5 = 3.1

⎜ 0.811 ⎠

⎟ sec

( ) 2

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