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Technical documentation and software quality assurance for project ...

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€<br />

€<br />

€<br />

€<br />

€<br />

C =1000exp( −100R)<br />

+ 0.8<br />

<strong>and</strong> the Richardson number,<br />

( ) =<br />

ξ D s<br />

⎛<br />

⎜<br />

⎝<br />

g<br />

2 2<br />

Ds u j<br />

⎞<br />

⎟<br />

⎠<br />

1<br />

3<br />

Ds €<br />

ξ( Ds), based on<br />

Chamberlain <strong>for</strong>mula <strong>for</strong> the width at frustum tip, W2 , is<br />

W2 = LB ( 0.18exp( −1.5R)<br />

+ 0.31)<br />

1− 0.47exp −25R<br />

€<br />

The surface area of the flame, A, is calculated as:<br />

A = π<br />

4 W1 2 2 ( + W2 ) + π<br />

2 W1 + W ⎡<br />

2 ⎢<br />

⎣<br />

( ) R L<br />

€<br />

27<br />

D s<br />

( ( ) )<br />

⎛<br />

⎜<br />

⎝<br />

2 + W 2 −W 1<br />

The fraction of the heat, Fs radiated from the flame surface was determined from<br />

experimental data <strong>and</strong> the curve is:<br />

Fs = 0.21exp( −0.00323u j € ) + 0.11<br />

2<br />

2<br />

⎞ ⎤<br />

⎟ ⎥<br />

⎠ ⎦<br />

The view factor F is defined by Sparrow <strong>and</strong> Cess, equation 4-14:<br />

dA cos β i cos β jdA<br />

i<br />

dFA − =<br />

j dAi<br />

A ∫A<br />

2<br />

j π r<br />

j<br />

where:<br />

A is the area of the radiating surface,<br />

j<br />

dA i is the receiving element,<br />

j<br />

β i is the angle between the normal to the receiving element <strong>and</strong> the line between the<br />

element <strong>and</strong> the radiating surface,<br />

β is the angle between the normal to the radiating surface at a point <strong>and</strong> the line<br />

j<br />

between that point <strong>and</strong> the receiving element,<br />

r is the distance between the point on the radiating surface <strong>and</strong> the receiving element.<br />

For a radiating surface of area i<br />

A <strong>and</strong> a receiving element of area j<br />

dA , we can let<br />

q' = incident radiation intensity per unit area, <strong>and</strong><br />

E' = emissive power per unit area,<br />

so<br />

1<br />

2

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