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Ernst Hansen: Measure Theory List of relevant errors

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<strong>Ernst</strong> <strong>Hansen</strong>: <strong>Measure</strong> <strong>Theory</strong><br />

Third Edition<br />

<strong>List</strong> <strong>of</strong> <strong>relevant</strong> <strong>errors</strong><br />

October 28, 2008<br />

EH<br />

This is a list <strong>of</strong> the <strong>errors</strong> in <strong>Ernst</strong> <strong>Hansen</strong>: <strong>Measure</strong> theory, third edition,<br />

deemed to be a potential source <strong>of</strong> confusion.<br />

100 7 Original: then the function x ↦→ lim sup n∈N fn(x) is also an Mfunction.<br />

Correct: then the function x ↦→ lim sup n→∞ fn(x) is also an Mfunction.<br />

Reported by: Niels Richard <strong>Hansen</strong><br />

138 9 Original: 6.2 Let f ∈ M + (R, B) be a non-negative measurable<br />

function.<br />

Correct: 6.2 Let f ∈ M + (R, B) be a non-negative measurable<br />

function.<br />

Reported by: Magnus Tor Ry Hessler<br />

139 8 Original:<br />

Correct:<br />

µ ({x|X | f(x) = ∞}) = 0 .<br />

µ ({x ∈ X | f(x) = ∞}) = 0 .<br />

Reported by: Magnus Tor Ry Hessler<br />

1


1692 Original: We see by the collage lemma that f has measurable<br />

sections,<br />

Correct: We see by lemma 4.11 that f has measurable sections,<br />

Reported by: Niels Richard <strong>Hansen</strong><br />

171 1 Original: We see by the collage lemma that f has measurable<br />

sections,<br />

Correct: We see by lemma 4.11 that f has measurable sections,<br />

Reported by: Niels Richard <strong>Hansen</strong><br />

174 ′′ 7 Original: Next, consider two H-sets G1⊆G2.<br />

Correct: Next, consider two H-sets G1 ⊂ G2.<br />

Reported by: Magnus Tor Ry Hessler<br />

17411 Original: Assume that G1⊆G2⊆... is an increasing sequence <strong>of</strong><br />

H-sets,<br />

Correct: Assume that G1 ⊂ G2 ⊂ . . . is an increasing sequence <strong>of</strong><br />

H-sets,<br />

Reported by: Magnus Tor Ry Hessler<br />

194 10 Original:<br />

µ1⊗. . .⊗µn(A1×. . .×An) =<br />

for Ai ∈ Ei, i = 1, . . .,n.<br />

Correct:<br />

µ1⊗. . .⊗µn(A1×. . .×An) =<br />

n�<br />

µi(Ai) for A1 ∈ E1, . . .,An ∈ En ,<br />

i=1<br />

n�<br />

µi(Ai) for A1 ∈ E1, . . .,An ∈ En .<br />

i=1<br />

Reported by: Magnus Tor Ry Hessler<br />

2


19710 Original: �<br />

−e −x − 1<br />

2 e−2x<br />

�∞ 0<br />

Correct: �<br />

−e −x + 1<br />

2 e−2x<br />

�∞ 0<br />

Reported by: Magnus Tor Ry Hessler<br />

1971 Original: as we saw in theorem 2.21,<br />

Correct: as we saw in lemma 2.21,<br />

Reported by: Magnus Tor Ry Hessler<br />

201 12 Original: Interchanging the order <strong>of</strong> integration in successive integrals<br />

cannot be performed freely if the integrand is non-negative<br />

Correct: Interchanging the order <strong>of</strong> integration in successive integrals<br />

cannot be performed freely unless the integrand is nonnegative<br />

Reported by: Ninna Reitzel Jensen<br />

2011 Original:<br />

Correct:<br />

y ↦→ a coste −ty + b sin t e −ty ,<br />

t ↦→ a coste −ty + b sin t e −ty .<br />

Reported by: Magnus Tor Ry Hessler<br />

3


30812 Original: The coefficients <strong>of</strong> the power series (14.2) are nonnegative<br />

Correct: The coefficients <strong>of</strong> the power series (14.3) are nonnegative<br />

Reported by: Ninna Reitzel Jensen<br />

30812 Original: The coefficients <strong>of</strong> the power series (14.2) are nonnegative<br />

Correct: The coefficients <strong>of</strong> the power series (14.3) are nonnegative<br />

Reported by: Ninna Reitzel Jensen<br />

360 5 Original: �<br />

Correct: �<br />

�<br />

|X| dP =<br />

�<br />

|X| dP =<br />

(|X|≤C)<br />

(|X|≤C)<br />

Reported by: Magnus Tor Ry Hessler<br />

392 7 Original: for some n ∈ N.<br />

Correct: for some n = 2, 3, . . ..<br />

Reported by: <strong>Ernst</strong> <strong>Hansen</strong><br />

4<br />

X dP<br />

|X| dP


49511 Original:<br />

Correct:<br />

tn(x1, . . .,xn) ∈ S(N, n) for (x1, . . ., xN) ∈ X n ,<br />

tn(x1, . . .,xn) ∈ S(N, n) for (x1, . . ., xn) ∈ X n ,<br />

Reported by: Tilde Stadel Borum<br />

5684 Original: The last inequality is due to the continuity <strong>of</strong> fN,<br />

Correct: The last equality is due to the continuity <strong>of</strong> fN,<br />

Reported by: Kang Li<br />

5

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