24.05.2018 Views

integration

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

378 INTEGRAL CALCULUS<br />

At the points of intersection the co-ordinates of the<br />

curves are equal. Since y = x 2 then y 2 = x 4 . Hence<br />

equating the y 2 values at the points of intersection:<br />

x 4 = 8x<br />

from which, x 4 − 8x = 0<br />

and x(x 3 − 8) = 0<br />

Hence, at the points of intersection, x = 0 and x = 2.<br />

When x = 0, y = 0 and when x = 2, y = 4. The<br />

points of intersection of the curves y = x 2 and<br />

y 2 = 8x are therefore at (0,0) and (2,4). A sketch is<br />

shown in Fig. 38.8. If y 2 = 8x then y = √ 8x.<br />

Shaded area<br />

=<br />

∫ 2<br />

0<br />

⎡<br />

= ⎣ ( 3<br />

√ ) x 2<br />

8<br />

(√<br />

8x − x<br />

2 ) dx =<br />

3<br />

2<br />

⎤<br />

− x3 ⎦<br />

3<br />

2<br />

0<br />

∫ 2<br />

0<br />

(√<br />

8<br />

)<br />

x 1 2 − x 2 )<br />

dx<br />

{√ √ }<br />

8 8<br />

= − 8 −{0}<br />

3<br />

3<br />

2<br />

= 16 3 − 8 3 = 8 3 = 22 square units<br />

3<br />

Figure 38.8<br />

The volume produced by revolving the shaded area<br />

about the x-axis is given by:<br />

{(volume produced by revolving y 2 = 8x)<br />

− (volume produced by revolving y = x 2 )}<br />

i.e. volume =<br />

= π<br />

∫ 2<br />

0<br />

∫ 2<br />

0<br />

π(8x)dx −<br />

∫ 2<br />

0<br />

(8x − x 4 )dx = π<br />

π(x 4 )dx<br />

[(<br />

= π 16 − 32 ) ]<br />

− (0)<br />

5<br />

= 9.6π cubic units<br />

Now try the following exercise.<br />

Exercise 150<br />

[<br />

8x 2<br />

2 − x5<br />

5<br />

Further problems on volumes<br />

1. The curve xy = 3 is revolved one revolution<br />

about the x-axis between the limits x = 2 and<br />

x = 3. Determine the volume of the solid<br />

produced.<br />

[1.5π cubic units]<br />

2. The area between y<br />

x 2 = 1 and y + x2 = 8is<br />

rotated 360 ◦ about the x-axis. Find the volume<br />

produced. [170 2 3π cubic units]<br />

3. The curve y = 2x 2 +3 is rotated about (a) the<br />

x-axis between the limits x = 0 and x = 3,<br />

and (b) the y-axis, between the same limits.<br />

Determine the volume generated in each case.<br />

[(a) 329.4π (b) 81π]<br />

4. The profile of a rotor blade is bounded by the<br />

lines x = 0.2, y = 2x, y = e −x , x = 1 and the<br />

x-axis. The blade thickness t varies linearly<br />

with x and is given by: t = (1.1 − x)K, where<br />

K is a constant.<br />

(a) Sketch the rotor blade, labelling the<br />

limits.<br />

(b) Determine, using an iterative method, the<br />

value of x, correct to 3 decimal places,<br />

where 2x = e −x<br />

(c) Calculate the cross-sectional area of the<br />

blade, correct to 3 decimal places.<br />

(d) Calculate the volume of the blade in terms<br />

of K, correct to 3 decimal places.<br />

[(b) 0.352 (c) 0.419 square units<br />

(d) 0.222 K]<br />

38.5 Centroids<br />

A lamina is a thin flat sheet having uniform thickness.<br />

The centre of gravity of a lamina is the point<br />

] 2<br />

0

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!