R - Széchenyi István Egyetem
R - Széchenyi István Egyetem
R - Széchenyi István Egyetem
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1 3 5<br />
Példák<br />
R = R + R + R = 1+ 1+ 1= 3 kΩ<br />
h<br />
R ⋅ R 11 ⋅<br />
= = = 0.3 Ω<br />
1 5 R6k Rh<br />
3<br />
R ⋅ R 11 ⋅<br />
= = = 0.3 Ω<br />
3 5 R7k Rh<br />
3<br />
R ⋅ R 11 ⋅<br />
= = = 0.3 Ω<br />
3 1 R8k Rh<br />
3<br />
RAB = R8 + (( R6 + R2) × ( R7 + R4))<br />
2.3⋅2.3 RAB = 0.3 + = 1.5 kΩ<br />
2.3+ 2.3<br />
Elektrotechnika 77
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