6. Zuren en basen
6. Zuren en basen
6. Zuren en basen
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Waterconstante<br />
• H 2O + H 2O OH - + H 3O +<br />
K c = [OH - ] e.[H 3O + ] e /[H 2O] e²<br />
= 10 -7 mol/l x 10 -7 mol/l / (55,5 mol/l)²<br />
= 3,25.10 -18 (⇒ ev<strong>en</strong>wicht naar links)<br />
• [H 2O] e = 55,5 mol/l (cte)<br />
⇒ K w = [OH - ] e.[H 3O + ] e<br />
= 10 -7 mol/l x 10 -7 mol/l<br />
= 10 -14 (Waterconstante)<br />
• pK w = -log K w = 14 = pH + pOH