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Chemisch evenwicht

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• N2 + 3 H2 2 NH3 [NH3] e= 0,102 mol/l<br />

[N2] e= 1,03 mol/l<br />

[H [H2] 2] e= e= 1,62 mol/<br />

Oefeningen p. 95<br />

K c ?<br />

• 2 SO2 + O2 2 SO3 (20 l) Kc ?<br />

2,5 mol SO2 (t0) 3,0 mol O2 (t0) → 2,0 mol O2 (te) 4,0 mol SO3 (t0)

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