Transformation av spänningar - Tillämpad fysik och elektronik ...

σx = 9 MP a σy = 3 MP a τxy = 3 √ 3 MP a
σ1 = 12MP a Φ1 = 30 ◦ σ2 = 0 Φ2 = 120 ◦
Mv a h
σ1 = − Mv
2πa 2 h σ2 = Mv
2πa 2 h σ3 = 0
p
Mv = πpa 3 2a
h
σ1,2 = (1 ± √ 2) pa
2h Φ1 = 112, 5 ◦ Φ2 = 22, 5 ◦
p Mv = πpa 3
a h
σ1,2 = (3 ± √ 5) pa
4h Φ1 = 121.7 ◦ Φ2 = 31.7 ◦
45 ◦
σu = 330 MP a
Mv = 1.75 kNm
a h
π/9
Mv
σ(φ) = Mv
2πa2h sin 40◦ τ(φ) = Mv
2πa2 cos 40◦ h
a
h
Mv
x ρ
σ1,2 = ρgx
2 ±
( ρgx
2 )2 + ( Mv
2πa2h )2
τmax = ( ρgx
2 )2 + ( Mv
2πa2h )2