Predavanje 1 - phy
Predavanje 1 - phy
Predavanje 1 - phy
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ENERGIJA U JEDNOSTAVNOM HARMONIJSKOM<br />
TITRANJU<br />
E = 1 2 mv 2 x<br />
+ 1 2 kx2 = const.<br />
(zakon očuvanja energije)<br />
u trenutku t = 0, v x = 0, x = A:<br />
E = 1 2 mv 2 x<br />
+ 1 2 kx2 = 1 ukupna energija H.O.<br />
2 kA2<br />
izvod:<br />
E = 1 2 mv 2 x<br />
+ 1 2 kx2 = 1 2<br />
( )<br />
m ⎡ ⎣−ω Asin ωt + φ ⎤⎦ 2 + 1 2<br />
= 1 2 kA2 sin 2 ( ωt + φ) + 1 2 kA2 cos 2 ( ωt + φ)<br />
k ⎡ ⎣Acos ( ωt + φ ) ⎤⎦ 2 =<br />
= 1 2 kA2<br />
Monday, March 14, 2011