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The Second Book of Mathematical Puzzles and Diversions

The Second Book of Mathematical Puzzles and Diversions

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Tetraflexagons 31<br />

gethe'r to make a flat square, but make sure that the two<br />

inside flaps go in opposite directions (lle) . Open the square<br />

as in drawing llf, then pull corner C down <strong>and</strong> to the left<br />

to make the flat structure shown in drawing llg. Corner D<br />

is now pushed to the left, behind the structure, creating the<br />

flat rectangle <strong>of</strong> drawing llh. This rectangle opens to form<br />

a cubical tube (lli) that is half the height <strong>of</strong> the original one.<br />

You are now at the mid-point <strong>of</strong> your operations; exactly<br />

half the tube has been reversed. Flatten the tube to make a<br />

rectangle again (llj), but flatten it in the opposite way<br />

from that shown in drawing llh. Starting as shown in<br />

drawing Ilk, the previous operations are now "undone," so<br />

to speak, by performing them in reverse. Result: a reversed<br />

flexatube. At least two other completely different methods<br />

<strong>of</strong> turning the flexatube inside out are known, both as de-<br />

vious <strong>and</strong> difficult to discover as this one.<br />

Recently Stone has been able to prove that a cylindrical<br />

b<strong>and</strong> <strong>of</strong> ang width can be turned inside out by a finite num-<br />

ber <strong>of</strong> folds along straight lines, but the general method is<br />

much too involved to describe here. <strong>The</strong> question arises : Can<br />

a paper bag (that is, a rectangular tube closed on the bot-<br />

tom) be turned inside out by a finite number <strong>of</strong> folds? This<br />

is an unsolved problem. Apparently the answer is no, re-<br />

gardless <strong>of</strong> the bag's proportions, though it probably would<br />

be extremely difficult to find a satisfactory pro<strong>of</strong>.

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