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The Second Book of Mathematical Puzzles and Diversions

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Digital Roots 49<br />

divided by 9. This is not hard to prove, <strong>and</strong> perhaps an in-<br />

formal statement <strong>of</strong> a pro<strong>of</strong> will interest some readers.<br />

Consider a four-digit number, say 4,135. This can be writ-<br />

ten as sums <strong>of</strong> powers <strong>of</strong> 10 :<br />

If 1 is subtracted from each power <strong>of</strong> 10, we can write<br />

the same number like this :<br />

(4 x 999) + (1 x 99) + (3 x 9) + (5 x 0) + 4 + 1 + 3 + 5<br />

<strong>The</strong> expressions inside the. parentheses are all multiples<br />

<strong>of</strong> 9. After casting them out, we are left with 4 + 1 + 3 + 5,<br />

the digits <strong>of</strong> the original number.<br />

In general, a number written with the digits abed can<br />

be written :<br />

(aX999) + (bX99) + (cX9) + (dXO) +a+b+c+d<br />

<strong>The</strong>refore a + b + c + d must be a remainder after cer-<br />

tain multiples <strong>of</strong> 9 are cast out. This remainder <strong>of</strong> course<br />

may be a number <strong>of</strong> more than one digit. If so, the same<br />

procedure will show that the sum <strong>of</strong> its digits will give<br />

another remainder after other multiples <strong>of</strong> 9 are cast out,<br />

<strong>and</strong> we can continue until only one digit, the digital root,<br />

remains. Such a procedure can be applied to any number,<br />

no matter how large. <strong>The</strong> digital root, therefore, is the num-<br />

ber that remains after the maximum number <strong>of</strong> 9's have<br />

been cast out; that is, after the number is divided by 9.<br />

Digital roots are <strong>of</strong>ten useful as negative checks in deter-<br />

mining whether a very large number is a perfect square or<br />

cube. All square numbers have digital roots <strong>of</strong> 1, 4, 7 or 9,<br />

<strong>and</strong> the last digit <strong>of</strong> the number cannot be 2, 3, 7 or 8. A<br />

cube may end with any digit, but its digital root must be 1,<br />

8 or 9. Most curiously <strong>of</strong> all, an even perfect number (<strong>and</strong><br />

so far no odd perfect number has been found) must end in<br />

6 or 28 <strong>and</strong>, with the exception <strong>of</strong> 6, the smallest perfect<br />

number, have a digital root <strong>of</strong> 1.

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