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AIRY STRESS FUNCTION FOR TWO DIMENSIONAL INCLUSION ...

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σ<br />

σ<br />

x<br />

y<br />

( ± l, y) = S,<br />

( x, ± c)<br />

= 0,<br />

τ ( ± l, y) = τ ( x, ± c)<br />

= 0,<br />

xy xy<br />

σ r ( ± a, ± a) − τ rθ<br />

( ± a, ± a)<br />

= 0.<br />

Solving for the Airy stress function, we get<br />

2 2 2 2 2<br />

2 2<br />

2 2<br />

S( x − y )( − 6a + x + y ) + 12b0 x( a − y ) + 12a0<br />

x( a − y )<br />

φ ( x, y)<br />

=<br />

2 2<br />

.<br />

12(<br />

a − y )<br />

19<br />

(3.1.4)<br />

(3.1.5)<br />

From the above result we can see that the Airy stress function is an indefinite<br />

value. Therefore, we can conclude that for a finite plate with a central hole infinite<br />

series having appropriate boundary conditions has to be taken into consideration to get a<br />

valid solution.<br />

3.2 Infinite Plate with a Hole Subjected to Tensile Loading<br />

Consider an infinite plate with a central hole subjected to uniform tensile far<br />

∞<br />

field loading σ x = S in the x direction. From (2.3.4), we get the complex potentials to<br />

be<br />

m<br />

∑<br />

Fk<br />

∞ ∞<br />

σ σ<br />

k<br />

x +<br />

= 1<br />

y **<br />

γ ( z)<br />

= − log z + z + γ ( z),<br />

2π ( 1 + κ ) 4<br />

m<br />

∑<br />

κ Fk<br />

∞ ∞ ∞<br />

σ σ iτ<br />

k<br />

y − x + 2<br />

= 1<br />

xy **<br />

ψ ( z)<br />

= log z +<br />

z + ψ ( z),<br />

2π ( 1 + k)<br />

2<br />

where Fk is the resultant force on the central hole, but the logarithmic part of the<br />

equations is omitted as it corresponds to discontinuity in the displacements or

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