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AIRY STRESS FUNCTION FOR TWO DIMENSIONAL INCLUSION ...

AIRY STRESS FUNCTION FOR TWO DIMENSIONAL INCLUSION ...

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3.3.2 Infinite Plate Surrounding the Disc<br />

Deriving the stress and displacement components for the part outside the<br />

inclusion which material constant κ1 which depends only on the Poisson’s Ratio and a<br />

shear modulus of µ1 .From (2.3.4) and (2.3.5) at r = a yields<br />

u<br />

out 1 4 4 2<br />

σ rr = 4 ( a S + a S cos2θ + 2a b1 + 4ab2<br />

cosθ<br />

2a<br />

2<br />

+ 6b cos2θ − 8a a cos2θ − 20aa cos 3θ<br />

),<br />

3<br />

1 2<br />

out 1 4 4 2<br />

σ θθ = 4 ( a S − a S cos2θ − 2a b1 − 4ab2<br />

cosθ<br />

2a<br />

− 6b cos2θ + 4aa cos 3θ<br />

),<br />

3 2<br />

out 1 4<br />

τ rθ<br />

= 4 ( − a S sin 2θ + 4ab2 sin θ + 6b3 sin 2θ<br />

2a<br />

2<br />

− 4a a sin2θ − 12aa sin 3θ<br />

),<br />

1 2<br />

out 1 4 4<br />

4 2<br />

ur<br />

= 3 ( − a S + a Sκ 1 − 2a S cos2θ<br />

− 4a<br />

b<br />

8a<br />

µ<br />

out<br />

θ<br />

1<br />

2<br />

− 4ab cosθ − 4b cos2θ + 4a a cos2θ<br />

2 3<br />

2<br />

+ 4a κ a cos2θ + 8aa cos3θ + 4aκ a cos 3θ<br />

),<br />

1 1 2 1 2<br />

1 4<br />

2<br />

= 3 ( − a S sin2θ − 2ab2 sin θ − 2b3 sin 2θ + 2a a1<br />

sin2θ<br />

4a<br />

µ<br />

1<br />

2<br />

− 2a κ a sin2θ + 4a sin3θ − 2aκ a sin 3θ<br />

).<br />

1 1 2 1 2<br />

26<br />

1<br />

1<br />

(3.3.8)<br />

(3.3.9)<br />

The continuity condition can be satisfied if the traction force and displacements<br />

are the same at the interface.<br />

Equating (3.3.6) to (3.3.8) and (3.3.7) to (3.3.9) we get the following equations:

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