Chapter 2 C apte DIODE Part ７ Sinusoidal Inputs: Half-Wave ... - FKE
Chapter 2 C apte DIODE Part ７ Sinusoidal Inputs: Half-Wave ... - FKE
Chapter 2 C apte DIODE Part ７ Sinusoidal Inputs: Half-Wave ... - FKE
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(b) Replace the ideal diode with a silicon diode.<br />
Solution<br />
V dc = - 0.318 (V m - V T )= - 0.318 (20 – 0.7 )= -0.318 (19.3 V) = - 6.14 V<br />
The resulting drop in dc level<br />
is 0.22 V (6.36 - 6.14 V)<br />
or about 3.5%.<br />
(c) Vm is increased to 200 V and compare solutions using Eq.(1) and Eq.(2)<br />
Solution<br />
E Eq.(1) (1) V Vdc = - 00.318 318 V Vm = - 00.318 318 (200 ) )= - 63 63.6 6 V<br />
Eq.(2) Vdc = - 0.318 (Vm - VT )= - 0.318 (200 – 0.7 )= -0.318 (199.3 V) = - 63.38 V<br />
The difference is very small that can be ignored.<br />
<strong>Ch<strong>apte</strong>r</strong> 2 <strong>DIODE</strong>, <strong>Part</strong> 7 <strong>Half</strong>-<strong>Wave</strong> Rectification 7
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