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principles of extraction and the extraction of semivolatile organics ...

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62 <strong>principles</strong> <strong>of</strong> <strong>extraction</strong><br />

Example<br />

A 1-L aqueous sample containing 100 parts per billion (ppb) <strong>of</strong> a compound<br />

having a molecular weight <strong>of</strong> 250 g/mol is extracted once with 150 mL <strong>of</strong><br />

organic extracting solvent. Assume that <strong>the</strong> KD value is 5. Given this information,<br />

<strong>the</strong> molarity <strong>of</strong> <strong>the</strong> original sample is 4:0 10 10 M. Calculate <strong>the</strong><br />

percent <strong>of</strong> <strong>the</strong> analyte extracted into <strong>the</strong> organic extracting solvent at<br />

equilibrium.<br />

Step 1. Calculate <strong>the</strong> moles <strong>of</strong> analyte in <strong>the</strong> original sample.<br />

Therefore,<br />

moles in original sample ¼ molarity <strong>of</strong> sample ðin mol=LÞ<br />

volume extracted ðin LÞ<br />

moles in original sample ¼ 4:0 10 10 M 1L¼ 4:0 10 10 mol ð2:25Þ<br />

Step 2. Calculate <strong>the</strong> moles <strong>of</strong> analyte left in <strong>the</strong> aqueous phase after <strong>extraction</strong>.<br />

ðmoles in original sample moles left in water after <strong>extraction</strong>Þ=<strong>extraction</strong> solvent volume ðin LÞ<br />

KD ¼<br />

moles left in water after <strong>extraction</strong>=volume <strong>of</strong> original sample ðin LÞ<br />

ð2:26Þ<br />

Therefore,<br />

moles left in water<br />

after <strong>extraction</strong><br />

such that,<br />

moles in original sample<br />

¼<br />

f½KD <strong>extraction</strong> solvent volume ðin LÞŠ=volume <strong>of</strong> original sample ðin LÞg þ 1<br />

moles left in water after <strong>extraction</strong><br />

4:0 10<br />

¼<br />

10 mol<br />

½ð5 0:150 LÞ=1 LŠþ1 ¼ 2:2857 10 10 mol<br />

Step 3. Calculate <strong>the</strong> moles <strong>of</strong> analyte extracted into layer B (i.e., <strong>the</strong><br />

extracting solvent) at equilibrium.<br />

moles <strong>of</strong> analyte extracted into organic solvent<br />

¼ moles <strong>of</strong> analyte in original sample moles left in water after <strong>extraction</strong><br />

¼ 4:0 10 10 mol 2:2857 10 10 mol ¼ 1:7143 10 10 mol ð2:27Þ

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